A Supplement to the Elements of EuclidJ. Deighton and Sons, Cambridge and G and W. B. Whittaker, Ave-Maria-Lane, 1819 - 410 sider |
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Side 4
... ( E. 10. 1. ) AB in C ; from C draw ( E. 11. 1. ) CD 1 to AB , meeting XY in D. The point D is equidistant from A , B. ACD , For , join A , D and B , D. Then , since ( constr . ) AC BC , and CD is common to the two BCD , and that ( constr ...
... ( E. 10. 1. ) AB in C ; from C draw ( E. 11. 1. ) CD 1 to AB , meeting XY in D. The point D is equidistant from A , B. ACD , For , join A , D and B , D. Then , since ( constr . ) AC BC , and CD is common to the two BCD , and that ( constr ...
Side 7
... E , F , shall all meet in a point that is equidistant from A , B and C. - For , draw ( E. 11. 1. ) DGL to AB , and EG L to AC , and let them meet in G : Join G , F. Then , ( constr . and S. 3. 1. Cor . 2 ... ) BG AG , and AG CG ; ... CG ...
... E , F , shall all meet in a point that is equidistant from A , B and C. - For , draw ( E. 11. 1. ) DGL to AB , and EG L to AC , and let them meet in G : Join G , F. Then , ( constr . and S. 3. 1. Cor . 2 ... ) BG AG , and AG CG ; ... CG ...
Side 23
... e . to divide it into three equal parts . Let the XAY be a right 4 : It is required A A luis BX E D Y Jed SLYA SAYA ... draw ( E. 12. 1. ) AD 1 to BC : The XAY is trisected by the two straight lines AC and AD . For , from C draw ( E. 12 ...
... e . to divide it into three equal parts . Let the XAY be a right 4 : It is required A A luis BX E D Y Jed SLYA SAYA ... draw ( E. 12. 1. ) AD 1 to BC : The XAY is trisected by the two straight lines AC and AD . For , from C draw ( E. 12 ...
Side 24
... ( E. 26. 1. ) the EAC - DAC : Again , since ( constr . and E. 5. 1. cor . ) the ACB = 2 ABC , and ( constr . ) the at ... Draw ( E. 11. 1. ) from A , 24 A SUPPLEMENT TO THE.
... ( E. 26. 1. ) the EAC - DAC : Again , since ( constr . and E. 5. 1. cor . ) the ACB = 2 ABC , and ( constr . ) the at ... Draw ( E. 11. 1. ) from A , 24 A SUPPLEMENT TO THE.
Side 27
... Draw ( E. 11. 1. ) from B , BY 1 to AB ; bisect A B E F ( E. 9.1 . ) the CBY by BD , meeting AC , pro- duced in D ; through D , draw ( E. 31. 1. ) DE parallel to BY , and let DE cut BC in F : Fis the point which was to be found . L For ...
... Draw ( E. 11. 1. ) from B , BY 1 to AB ; bisect A B E F ( E. 9.1 . ) the CBY by BD , meeting AC , pro- duced in D ; through D , draw ( E. 31. 1. ) DE parallel to BY , and let DE cut BC in F : Fis the point which was to be found . L For ...
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ABCD base BC bisect centre chord circle ABC circle described circumference constr decagon describe a circle describe the circle diameter distance divided double draw a straight draw E equi equiangular equilateral and equiangular F draw find a point finite straight line given circle given finite straight given point given ratio given square given straight line half hypotenuse inscribed isosceles less Let AB Let ABC lines be drawn magnitudes manifest manner meet the circumference number of equal number of sides parallel to BC parallelogram pass perimeter point G polygon PROBLEM produced PROP rectangle contained rectilineal figure remaining sides required to describe required to draw rhombus right angles segment semi-diameter straight line joining tangent THEOREM three given touch the circle trapezium vertex