Elements of geometry, containing books i. to vi.and portions of books xi. and xii. of Euclid, with exercises and notes, by J.H. Smith |
Inni boken
Resultat 1-5 av 48
Side 7
... passes through the other extremity of that line . The restriction is , that the compasses are not supposed to be capable of conveying distances . Post . IV . and v . refer to simple geometrical facts , which Euclid desires to take for ...
... passes through the other extremity of that line . The restriction is , that the compasses are not supposed to be capable of conveying distances . Post . IV . and v . refer to simple geometrical facts , which Euclid desires to take for ...
Side 18
... passes through BC . B D Then in △ ABD , · : BD = BA , .. 2 BAD = 2 BDA , I. A. And in △ ACD , · . · CD = CA , . : ≤ CAD = 2 CDA , I. A. ..sum of 4s BAD , CAD = sum of 4 s BDA , CDA , Ax . 2 . that is , L BACL BDC . Hence we see ...
... passes through BC . B D Then in △ ABD , · : BD = BA , .. 2 BAD = 2 BDA , I. A. And in △ ACD , · . · CD = CA , . : ≤ CAD = 2 CDA , I. A. ..sum of 4s BAD , CAD = sum of 4 s BDA , CDA , Ax . 2 . that is , L BACL BDC . Hence we see ...
Side 19
... pass through BC . B D I. A. I. A. Then in △ ABD , · . · BD = BA , : . △ BAD = △ BDA , And in △ ACD , ·· CD = CA , .. △ CAD = 2 CDA , Hence since the whole angles BAD , BDA are equal . and parts of these CAD , CDA are equal . .. the ...
... pass through BC . B D I. A. I. A. Then in △ ABD , · . · BD = BA , : . △ BAD = △ BDA , And in △ ACD , ·· CD = CA , .. △ CAD = 2 CDA , Hence since the whole angles BAD , BDA are equal . and parts of these CAD , CDA are equal . .. the ...
Side 65
... passing through A but AD is | to BC ; .. AD is to BC . Q. E. D. Ex . 1. AD is parallel to BC ; AC , BD meet in E ; BC is produced to P so that the triangle PEB is equal to the triangle ABC : shew that PD is parallel to AC . Ex . 2. If ...
... passing through A but AD is | to BC ; .. AD is to BC . Q. E. D. Ex . 1. AD is parallel to BC ; AC , BD meet in E ; BC is produced to P so that the triangle PEB is equal to the triangle ABC : shew that PD is parallel to AC . Ex . 2. If ...
Side 66
... passing through A but AD is || to BF , .. AD is to BF . Q. E. D. Ex . 1. The straight line , joining the points of bisection of two sides of a triangle , is parallel to the base , and is equal to half the base . Ex . 2. The straight ...
... passing through A but AD is || to BF , .. AD is to BF . Q. E. D. Ex . 1. The straight line , joining the points of bisection of two sides of a triangle , is parallel to the base , and is equal to half the base . Ex . 2. The straight ...
Vanlige uttrykk og setninger
AB=DE ABCD AC=DF angle equal angular points base BC BC=EF centre chord circumference coincide described diagonals diameter divided equal angles equiangular equilateral triangle equimultiples Eucl Euclid exterior angle given angle given circle given line given point given st given straight line greater Hence hypotenuse inscribed intersect isosceles triangle less Let ABC Let the st lines be drawn magnitudes middle points multiple opposite angles opposite sides parallel parallelogram pentagon perpendicular polygon produced Prop prove Q. E. D. Ex Q. E. D. PROPOSITION quadrilateral radius ratio rectangle contained rectilinear figure reflex angle rhombus right angles segment Shew shewn square straight lines drawn sum of sqq Take any pt tangent THEOREM together=two rt trapezium triangle ABC triangles are equal vertex vertical angle
Populære avsnitt
Side 42 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Side 53 - All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides.
Side 17 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz.
Side 23 - To draw a straight line perpendicular to a given straight line of an unlimited length, from a given point without it.
Side 106 - To draw a straight line through a given point parallel to a given straight line. Let A be the given point, and BC the given straight line ; it is required to draw a straight line through the point A, parallel to the straight hue BC.
Side 178 - The angle in a semicircle is a right angle; the angle in a segment greater than a semicircle is less than a right angle; and the angle in a segment less than a semicircle is greater than a right angle.
Side 188 - To describe an isosceles triangle, having each of the angles at the base double of the third angle.
Side 78 - If there be two straight lines, one of which is divided into any number of parts, the rectangle contained by the two straight lines is equal to the rectangles contained by the undivided line, and the several parts of the divided line.
Side 91 - In every triangle, the square on the side subtending either of the acute angles, is less than the squares on the sides containing that angle, by twice the rectangle contained by either of these sides, and the straight line intercepted between the acute angle and the perpendicular let fall upon it from the opposite angle, Let ABC be any triangle, and the angle at B one of its acute angles, and upon BC, one of the sides containing it, let fall the perpendicular AD from the opposite angle.
Side 5 - A circle is a plane figure contained by one line, which is called the circumference, and is such that all straight lines drawn from a certain point within the figure to the circumference, are equal to one another.