Euclid's Elements of geometry, books i. ii. iii. iv |
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Side 2
A semicircle is the figure contained by a diameter and the part of the circumference cut off by the diameter . 19. A segment of a circle is the figure contained by a straight line and the part of the circumference which it cuts off .
A semicircle is the figure contained by a diameter and the part of the circumference cut off by the diameter . 19. A segment of a circle is the figure contained by a straight line and the part of the circumference which it cuts off .
Side 67
Bisect BF in G ( I. 10 ) , and from the centre G , at the distance GB , or GF , describe the semicircle BHF ; A H B E D 4. Produce DE to H , and join GH ; Then the square described upon EH shall be equal to the rectilineal figure A.
Bisect BF in G ( I. 10 ) , and from the centre G , at the distance GB , or GF , describe the semicircle BHF ; A H B E D 4. Produce DE to H , and join GH ; Then the square described upon EH shall be equal to the rectilineal figure A.
Side 89
Hypothesis . - Let ABCD be a circle , and BAD , BED , angles in the same segment BAED . Sequence . The angles BAD , BED , shall be equal to one another . Case I. First , let the segment BAED be greater than a semicircle . Construction .
Hypothesis . - Let ABCD be a circle , and BAD , BED , angles in the same segment BAED . Sequence . The angles BAD , BED , shall be equal to one another . Case I. First , let the segment BAED be greater than a semicircle . Construction .
Side 90
For the same reason , because the segment CBED is greater than a semicircle , the angles CAD , CED , are equal . 3. Therefore the whole angle BAD is equal to the whole angle BED . ( ax . 2. ) Conclusion . Therefore , the angles in the ...
For the same reason , because the segment CBED is greater than a semicircle , the angles CAD , CED , are equal . 3. Therefore the whole angle BAD is equal to the whole angle BED . ( ax . 2. ) Conclusion . Therefore , the angles in the ...
Side 93
In the first case , it is evident that , because the centre D is in AC , the segment ABC is a semicircle . 12. In the second case , if the angle ABD be greater than BAD , the centre E falls without the segment ABC , which is therefore ...
In the first case , it is evident that , because the centre D is in AC , the segment ABC is a semicircle . 12. In the second case , if the angle ABD be greater than BAD , the centre E falls without the segment ABC , which is therefore ...
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Vanlige uttrykk og setninger
ABCD angle ABC angle BAC angle BCD angle equal assumed base base BC BC is equal bisected BOOK centre circle ABC circumference coincide common Conclusion const Construction Construction.-1 Demonstration Demonstration.-1 describe diameter distance divided double draw drawn equal equilateral exterior angle extremities fall figure four given circle given point given straight line Given.-Let greater half Hypothesis Hypothesis.-Let inscribed join less manner meet opposite angle parallel parallelogram pass pentagon perpendicular produced proved Q. E. D. PROPOSITION reason rectangle AB BC rectangle contained References-Prop regular right angles segment semicircle Sequence shown sides Sought square on AC Take third touches the circle triangle ABC twice the rectangle whole
Populære avsnitt
Side 25 - If two triangles have two angles of the one equal to two angles of the other, each to each ; and one side equal to one side, viz.
Side 2 - A circle is a plane figure contained by one line, which is called the circumference, and is such that all straight lines drawn from a certain point within the figure to the circumference, are equal to one another.
Side 99 - The angle in a semicircle is a right angle; the angle in a segment greater than a semicircle is less than a right angle; and the angle in a segment less than a semicircle is greater than a right angle.
Side 4 - If a straight line meets two straight lines, so as to " make the two interior angles on the same side of it taken " together less than two right angles...
Side 66 - ... the sides containing the obtuse angle, by twice the rectangle contained by the side upon which, when produced, the perpendicular falls, and the straight line intercepted without the triangle between the perpendicular and the obtuse...
Side 65 - To divide a given straight line into two parts, so that the rectangle contained by the whole, and one of the parts, may be equal to the square of the other part.
Side 32 - F, which is the common vertex of the triangles ; that is, together with four right angles. Therefore all the angles of the figure, together with four right angles, are equal to twice as many right angles as the figure has sides.
Side 58 - If a straight line be bisected, and produced to any point ; the rectangle contained by the whole line thus produced, and the part of it produced...
Side 88 - The straight line drawn at right angles to the diameter of a circle, from the extremity of it, falls without the circle...
Side 33 - The straight lines which join the extremities of two equal and parallel straight lines towards the same parts, are also themselves equal and parallel.
Bibliografisk informasjon
| Tittel | Euclid's Elements of geometry, books i. ii. iii. iv Scot. sch. book assoc. Progressive series |
| Forfatter | Euclides |
| distribuert | 1862 |
| Original fra | Oxford University |
| Digitalisert | 19. apr 2006 |
| Eksporter sitat | BiBTeX EndNote RefMan |