## The first three books of Euclid's Elements of geometry, with theorems and problems, by T. Tate |

### Inni boken

Resultat 1-5 av 5

Side 8

If two triangles have two sides of the one equal to two sides of the other , each to

each ; and have likewise the angles ... For , if the

, so that the point A may be on D , and the straight line AB upon DE ; the point B ...

If two triangles have two sides of the one equal to two sides of the other , each to

each ; and have likewise the angles ... For , if the

**triangle ABC**be applied to DEF, so that the point A may be on D , and the straight line AB upon DE ; the point B ...

Side 31

to DBCF , because they are upon the same base BC , and between the same

parallels BC , EF ; and the

because the diameter AB bisects it ( 1 . 34 . ) ; and the triangle DBC is the half of

the ...

to DBCF , because they are upon the same base BC , and between the same

parallels BC , EF ; and the

**triangle ABC**is the half of the parallelogram EBCA ,because the diameter AB bisects it ( 1 . 34 . ) ; and the triangle DBC is the half of

the ...

Side 32

A E parallel to BC , and join EC : The

triangle EBC , because it is upon the same base BC , and between the A D same

parallels BC , AE : But the

therefore ...

A E parallel to BC , and join EC : The

**triangle ABC**is equal ( 1. 37. ) to thetriangle EBC , because it is upon the same base BC , and between the A D same

parallels BC , AE : But the

**triangle ABC**is equal to the triangle BDC ( Hyp . ) ;therefore ...

Side 33

С the same base BC , and between the same D E parallels BC , AE ; the

parallelogram ABCD is double of the triangle EBC . Join Ac ; then the

BC , and ...

С the same base BC , and between the same D E parallels BC , AE ; the

parallelogram ABCD is double of the triangle EBC . Join Ac ; then the

**triangle****ABC**is equal ( 1. 37. ) to the triangle EBC , because they are upon the same baseBC , and ...

Side 93

To bisect a triangle by a line drawn from a given point in one of the sides . · Let

ABC be the triangle , and p the given point . Bisect BC in E ; join A E , PE ; from A

draw AF parallel to PE ; and join PF ; then PF will bisect the

To bisect a triangle by a line drawn from a given point in one of the sides . · Let

ABC be the triangle , and p the given point . Bisect BC in E ; join A E , PE ; from A

draw AF parallel to PE ; and join PF ; then PF will bisect the

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The first three books of Euclid's Elements of geometry, with theorems and ... Euclides Uten tilgangsbegrensning - 1851 |

The First Three Books of Euclid's Elements of Geometry from the Text of Dr ... Euclid,Thomas Tate Ingen forhåndsvisning tilgjengelig - 2014 |

The First Three Books of Euclid's Elements of Geometry from the Text of Dr ... Euclid,Thomas Tate Ingen forhåndsvisning tilgjengelig - 2014 |

### Vanlige uttrykk og setninger

ABCD alternate angle ABC angle ACB angle BAC angle equal base BC BC is equal bisect centre circle ABC circumference coincide common construct demonstrated describe diameter divided double draw equal angles equal to FB equilateral exterior angle extremity figure fore four given point given straight line gnomon greater impossible interior isosceles triangle join less Let ABC likewise line be drawn meet opposite angles opposite sides parallel parallelogram pass perpendicular PROB produced PROP Q. E. D. PROP rectangle contained remaining angle right angles segment semicircle shown sides squares of AC straight line AC Take taken THEOR third touch touches the circle triangle ABC twice the rectangle vertex wherefore whole

### Populære avsnitt

Side 6 - If a straight line meets two straight lines, so as to make the two interior angles on the same side of it taken together less than two right angles...

Side 5 - Let it be granted that a straight line may be drawn from any one point to any other point.

Side 20 - If two triangles have two sides of the one equal to two sides of the...

Side 30 - Parallelograms upon equal bases, and between the same parallels, are equal to one another.

Side 17 - Any two angles of a triangle are together less than two right angles. Let ABC be any triangle ; any two of its angles together are less than two right angles.

Side 84 - IF from a point without a circle there be drawn two straight lines, one of which cuts the circle, and the other meets it; if the rectangle contained by the whole line which cuts the circle, and the part of it without the circle, be equal to the square of the line which meets it, the line which meets it shall touch the circle.

Side 82 - If from any point without a circle two straight lines be drawn, one of -which cuts the circle, and the other touches it; the rectangle contained by the whole line which cuts the circle, and the part of it without the circle, shall be equal to the square of the line which touches it.

Side 11 - UPON the same base, and on the same side of it, there cannot be two triangles that have their sides which are terminated in one extremity of the base equal to one another, and likewise those which are terminated in the other extremity.

Side 19 - To make a triangle of which the sides shall be equal to three given straight lines, but any two whatever of these must be greater than the third, (i.

Side 7 - From the greater of two given straight lines to cut off a part equal to the less. Let AB and C be the two given straight lines, whereof AB is the greater.