 | Thomas Keith - 1810 - 478 sider
...ACB=/DCE = ZDFE (N. and Q. 131.) therefore the triangle ABC is equal to the triangle DEF (D. 136.); let the surface of each of these triangles be represented...circle of the sphere (as 1, 2, 3.) be divided into any nu.nber of equal parts, and through the points of division (1, 2, 3.) great circles be drawn so as... | |
 | Olinthus Gregory - 1815 - 604 sider
...end B of the time AB be represented by the line KB, drawn at pleasure to AB, and join AE. Divide AB into any number of equal parts, and through the points of division draw as many lines parallel to EB ; these will represent the increasing degrees of velocity after the... | |
 | Thomas Keith - 1826 - 504 sider
...АСВГ: ZDCE = Z.DFE (N. and Q. 135.) therefore the triangle ABC is equal to the triangle DEF (D. 141.); let the surface of each of these triangles be represented by m, and let TO, x, and y represent the surfaces of the triangles in which they are situated. Now it is plain, that... | |
 | Seth Eastman - 1837 - 114 sider
...distance SD, in front of the spectator, and draw AG perpendicular to the line of sight. Divide AG, and DN, into any number of equal parts, and through the points of division draw lines parallel to AG, and DN, so as to divide the surface of the plan into squares. Now there... | |
 | Joseph Gwilt - 1842 - 1114 sider
...the surface of the dome. Make Ai equal to half the width of a board and join ei. Divide the arc AB into any number of equal parts, and through the points of division draw the lines li, 2j, 5k, 41, cutting Ac in the points efgh and ei in the points ijtí. Produce the... | |
 | Charles Davies, William Guy Peck - 1855 - 592 sider
...draw through A and these points straight lines : these will be the projections of meridians. Divide FD into any number of equal parts, and through the points of division describe concentric circles having their centre at A ; these will be the projections of intermediate... | |
 | James Maurice Wilson - 1869 - 260 sider
...three parallels, PQR, LMN any two lines intersected by them ; then shall PQ : QR :: LM : MN. For if PQ be divided into any number of equal parts, and through the points of division lines be drawn parallel to A or B, LM will be divided by those lines into the same number of equal... | |
 | Dennis Hart Mahan - 1877 - 238 sider
...the taste. 2. To represent a pavement made up of squares. (PI. I.** Fig. 1.) Divide the lower side into any number of equal parts, and through the points of division draw lines 45° both ways ; if through the points where these diagonals meet the sides, diagonal lines... | |
 | William Frothingham Bradbury - 1877 - 262 sider
...common altitude ; then their bases will be in the same plane (VI. 11). Divide the common altitude, BX, into any number of equal parts, and through the points of division pass planes parallel to the plane of the bases. The corresponding sections thus formed of the pyramids... | |
 | George Anthony Hill - 1880 - 348 sider
...horizontal plane, and having equivalent bases ABC and MNO, and equal heights. Divide the common height into any number of equal parts, and through the points of division pass planes parallel to the bases of the pyramids. Since the bases are equivalent, it follows, from... | |
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Now it is plain, that if any great circle of the sphere (as 1, 2, 3.) be divided into any number of equal parts, and through the points of division... 
