Plane and Solid GeometryGinn, 1899 - 473 sider |
Inni boken
Resultat 1-5 av 66
Side v
... constructed . This method will furnish a valuable exercise as a language lesson , will cultivate the habit of neat and orderly arrangement of work , and will allow a brief interval for deliberating on each step . He After a Book has ...
... constructed . This method will furnish a valuable exercise as a language lesson , will cultivate the habit of neat and orderly arrangement of work , and will allow a brief interval for deliberating on each step . He After a Book has ...
Side vi
... constructing the figures , for choosing the best language , and for determining the best arrangement . The time necessary for the reading of examination books will be diminished by more than one half , if the use of symbols is allowed ...
... constructing the figures , for choosing the best language , and for determining the best arrangement . The time necessary for the reading of examination books will be diminished by more than one half , if the use of symbols is allowed ...
Side 112
... constructed . We now proceed to explain the methods of constructing simple problems , and after- wards to apply these methods to the solution of more difficult problems . PROPOSITION XXI . PROBLEM . 300. To let fall a perpendicular upon ...
... constructed . We now proceed to explain the methods of constructing simple problems , and after- wards to apply these methods to the solution of more difficult problems . PROPOSITION XXI . PROBLEM . 300. To let fall a perpendicular upon ...
Side 115
... construct an angle of 45 ° ; of 135 ° . Ex . 135. To construct an equilateral triangle , having given one side . Ex . 136. To construct an angle of 60 ° ; of 150 ° . Ex . 137. To trisect a right angle . PROPOSITION XXVI . PROBLEM . 305 ...
... construct an angle of 45 ° ; of 135 ° . Ex . 135. To construct an equilateral triangle , having given one side . Ex . 136. To construct an angle of 60 ° ; of 150 ° . Ex . 137. To trisect a right angle . PROPOSITION XXVI . PROBLEM . 305 ...
Side 116
... construct an angle equal to a given angle . A G M At C in the line CM , construct an angle equal to the given angle A. From A as a centre , with any radius , AE , describe an arc cutting the sides of the A at E and F. From Cas a centre ...
... construct an angle equal to a given angle . A G M At C in the line CM , construct an angle equal to the given angle A. From A as a centre , with any radius , AE , describe an arc cutting the sides of the A at E and F. From Cas a centre ...
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Vanlige uttrykk og setninger
ABCD AC² adjacent angles altitude angles are equal apothem axis bisector bisects called centre chord circumference circumscribed coincide construct cylinder denote diagonals diameter dihedral angles divided Draw equiangular equidistant equilateral triangle equivalent exterior angle feet Find the area Find the locus frustum given circle given line given point given straight line greater Hence homologous homologous sides hypotenuse inches inscribed intersecting isosceles triangle lateral area lateral edges limit middle point number of sides opposite parallel lines parallelogram parallelopiped perimeter perpendicular plane MN polyhedron prism prismatoid Proof proportional prove Q. E. D. PROPOSITION quadrilateral radii radius ratio rectangle regular polygon respectively rhombus right angle right circular right triangle segments similar slant height sphere spherical square surface tangent tetrahedron THEOREM trapezoid triangle ABC triangle is equal trihedral vertex vertices
Populære avsnitt
Side 274 - If two planes are perpendicular to each other, a straight line drawn in one of them, perpendicular to their intersection, is perpendicular to the other.
Side 50 - If the opposite sides of a quadrilateral are equal, the figure is a parallelogram.
Side 66 - If two triangles have two sides of the one equal respectively to two sides of the other, but the included angle of the first greater than the included angle of the second, then the third side of the first is greater than the third side of the second. Given A ABC and A'B'C...
Side 41 - If two angles of a triangle are unequal, the sides opposite are unequal, and the greater side is opposite the greater angle.
Side 169 - In any triangle the product of two sides is equal to the product of the diameter of the circumscribed circle by the altitude upon the third side.
Side 360 - A sphere is a solid bounded by a surface all points of which are equally distant from a point within called the centre.
Side 71 - The sum of the perpendiculars dropped from any point in the base of an isosceles triangle to the legs, is equal to the altitude upon one of the arms.
Side 156 - In a series of equal ratios, the sum of the antecedents is to the sum of the consequents as any antecedent is to its consequent.
Side 71 - The sum of the perpendiculars from any point within an equilateral triangle to the three sides is equal to the altitude of the triangle (Fig.
Side 383 - Hence the two last are right angles ; hence the arc drawn from the vertex of an isosceles spherical triangle to the middle of the base, is at right angles to the base, and bisects the vertical angle.