Euclidian Geometry |
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Resultat 1-5 av 88
Side vii
... circle have been discussed , and the groundwork laid for a comparison not only of the areas but also of the circumferences of circles . It has been deemed essential that Problems , though kept distinct from Theorems , should ...
... circle have been discussed , and the groundwork laid for a comparison not only of the areas but also of the circumferences of circles . It has been deemed essential that Problems , though kept distinct from Theorems , should ...
Side x
... Circles . Chords . Sup , to Book I. I 2 2 I , 3 a 9 4 14 5 15 25 6 CBC Tangents . 16 , 18 , 19 17 С 21 Parallels . Lemma 20 ........ 27 , 28 ( 29 ) m ......... II , 9 , 10 n Contact of OS , .31 p 2 Չ 3 .. 5 , 6 j 7 8 IO 22 ( 30 ) I. 21 ...
... Circles . Chords . Sup , to Book I. I 2 2 I , 3 a 9 4 14 5 15 25 6 CBC Tangents . 16 , 18 , 19 17 С 21 Parallels . Lemma 20 ........ 27 , 28 ( 29 ) m ......... II , 9 , 10 n Contact of OS , .31 p 2 Չ 3 .. 5 , 6 j 7 8 IO 22 ( 30 ) I. 21 ...
Side xv
... circle . Oce circumference . △ perpendicular ( to ) . Il parallel . = equal to . > greater than . < less than . ... because . ... therefore . : is to . The object aimed at is merely to place before the student the various steps of an ...
... circle . Oce circumference . △ perpendicular ( to ) . Il parallel . = equal to . > greater than . < less than . ... because . ... therefore . : is to . The object aimed at is merely to place before the student the various steps of an ...
Side 10
... circle is a plane figure contained by one line called the circumference , and is such that all straight lines drawn from a certain point within the figure to the circumference are equal . That point is called the centre of the circle ...
... circle is a plane figure contained by one line called the circumference , and is such that all straight lines drawn from a certain point within the figure to the circumference are equal . That point is called the centre of the circle ...
Side 11
... circle BCD , and with B as centre and radius BA describe the circle ACE . and Let these circles intersect in C ; join CA , CB . Then ABC shall be the equilateral triangle required . = BCD , .. AB is AC , .. AB is BC , ... A is the ...
... circle BCD , and with B as centre and radius BA describe the circle ACE . and Let these circles intersect in C ; join CA , CB . Then ABC shall be the equilateral triangle required . = BCD , .. AB is AC , .. AB is BC , ... A is the ...
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Algebra base Cambridge centre chord circumference cloth Conic Sections Crown 8vo Describe a circle diagonals diameter divided draw a straight ELEMENTARY TREATISE English equiangular equilateral Euclid Extra fcap fcap GEOMETRY given angle given circle given point given straight line Grammar greater H Let Hence inscribed intersecting isosceles triangle Latin Let ABC line bisecting locus Mathematical meet opposite angles Owens College parallel parallelogram perimeter perpendicular plane polygon PROBLEM produced Professor proportional PROPOSITION ratio rect rectangle rectangle contained rectilineal figure regular polygon respectively rhombus right angles Schools Second Edition segment similar Similarly squares on AC straight line drawn straight line joining tangent THEOREM TRIGONOMETRY twice rectangle twice the squares vertex