Euclidian Geometry |
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Side 56
... diameter of any parallelogram , are equal to one another . F P SA R H N Let FGHK be a , and GK one of its diagonals , and SR , PNs about the diagonal . Then FQ , QH , the remainings , which are called complements , shall be equal to one ...
... diameter of any parallelogram , are equal to one another . F P SA R H N Let FGHK be a , and GK one of its diagonals , and SR , PNs about the diagonal . Then FQ , QH , the remainings , which are called complements , shall be equal to one ...
Side 100
... diameter . PROPOSITION V. The diameter is the greatest chord of a circle , and of all others that nearer to the centre is greater than the more remote . G T H Let ACB be a diameter of the AGB , HK , FG chords of which HK is nearer to ...
... diameter . PROPOSITION V. The diameter is the greatest chord of a circle , and of all others that nearer to the centre is greater than the more remote . G T H Let ACB be a diameter of the AGB , HK , FG chords of which HK is nearer to ...
Side 118
... diameter , and AP a chord dividing the O APB into the segments ABP , AQP . Then shall the in the semi- circle APB be a right △ ; · the in the segment ABP greater than a semicircle < a right ≤ ; B and the in the segment AQP less than a ...
... diameter , and AP a chord dividing the O APB into the segments ABP , AQP . Then shall the in the semi- circle APB be a right △ ; · the in the segment ABP greater than a semicircle < a right ≤ ; B and the in the segment AQP less than a ...
Side 119
... diameter AD ; join DF . Then 4 AFD is a right angle ; = .. LS FDA , FAD are together a right ; ( III . 16 ) and .. DAT ; ( III . 2 ) = ¿ i.e.LS FAT , FAD together . Take away the common △ FAD . .. LFDAL FAT ; but AQF = ¿ FDA ; ( III ...
... diameter AD ; join DF . Then 4 AFD is a right angle ; = .. LS FDA , FAD are together a right ; ( III . 16 ) and .. DAT ; ( III . 2 ) = ¿ i.e.LS FAT , FAD together . Take away the common △ FAD . .. LFDAL FAT ; but AQF = ¿ FDA ; ( III ...
Side 126
... diameter AB . Then AB shall bisect the Oce . For the may be taken up , inverted and applied to its former position , so that AB may fall upon its former position . F Then will AGB fall upon AFB ; .. arc AGB : = arc AFB . COR . To divide ...
... diameter AB . Then AB shall bisect the Oce . For the may be taken up , inverted and applied to its former position , so that AB may fall upon its former position . F Then will AGB fall upon AFB ; .. arc AGB : = arc AFB . COR . To divide ...
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Algebra base Cambridge centre chord circumference cloth Conic Sections Crown 8vo Describe a circle diagonals diameter divided draw a straight ELEMENTARY TREATISE English equiangular equilateral Euclid Extra fcap fcap GEOMETRY given angle given circle given point given straight line Grammar greater H Let Hence inscribed intersecting isosceles triangle Latin Let ABC line bisecting locus Mathematical meet opposite angles Owens College parallel parallelogram perimeter perpendicular plane polygon PROBLEM produced Professor proportional PROPOSITION ratio rect rectangle rectangle contained rectilineal figure regular polygon respectively rhombus right angles Schools Second Edition segment similar Similarly squares on AC straight line drawn straight line joining tangent THEOREM TRIGONOMETRY twice rectangle twice the squares vertex