Euclidian Geometry |
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Resultat 1-5 av 48
Side 3
... fall otherwise as AOB , POQ having a common point O. P A Q B Then AOB might be turned about one extremity A towards the side on which OQ is , so as to cut OQ and also ОР . Thus two straight lines would enclose a space , which is ...
... fall otherwise as AOB , POQ having a common point O. P A Q B Then AOB might be turned about one extremity A towards the side on which OQ is , so as to cut OQ and also ОР . Thus two straight lines would enclose a space , which is ...
Side 4
... fall on E , and C will fall on F , AB is = DE , AC is = DF ; .. BC will coincide with EF . For if it fell otherwise , as EKF , then two straight lines . would enclose a space , which is impossible ; SO .. BC is = EF . Also the AABC will ...
... fall on E , and C will fall on F , AB is = DE , AC is = DF ; .. BC will coincide with EF . For if it fell otherwise , as EKF , then two straight lines . would enclose a space , which is impossible ; SO .. BC is = EF . Also the AABC will ...
Side 5
... fall along that of ABG ; also B would fall on that of C , · . · AB is = AC , and C on that of B for the same reason , .. BC would coincide with its former position . H Thus AB , BC would fall on the former positions of AC , CB ...
... fall along that of ABG ; also B would fall on that of C , · . · AB is = AC , and C on that of B for the same reason , .. BC would coincide with its former position . H Thus AB , BC would fall on the former positions of AC , CB ...
Side 6
... fall on EF ; then will BA fall along ED , . LABC is = L DEF , and CA will fall along FD , . LACB is = LDFE ; .. the point A will fall on the point D , .. the triangle ABC will coincide with the △ DEF , and is .. equal to it in all ...
... fall on EF ; then will BA fall along ED , . LABC is = L DEF , and CA will fall along FD , . LACB is = LDFE ; .. the point A will fall on the point D , .. the triangle ABC will coincide with the △ DEF , and is .. equal to it in all ...
Side 7
... fall on the former position of B and B on that of C ; then will CA fall along that of BA , · . · • △ ABC is = LACB , and BA along that of CA for the same reason ; .. A will fall on its former position , and .. AC will coincide exactly ...
... fall on the former position of B and B on that of C ; then will CA fall along that of BA , · . · • △ ABC is = LACB , and BA along that of CA for the same reason ; .. A will fall on its former position , and .. AC will coincide exactly ...
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Algebra base Cambridge centre chord circumference cloth Conic Sections Crown 8vo Describe a circle diagonals diameter divided draw a straight ELEMENTARY TREATISE English equiangular equilateral Euclid Extra fcap fcap GEOMETRY given angle given circle given point given straight line Grammar greater H Let Hence inscribed intersecting isosceles triangle Latin Let ABC line bisecting locus Mathematical meet opposite angles Owens College parallel parallelogram perimeter perpendicular plane polygon PROBLEM produced Professor proportional PROPOSITION ratio rect rectangle rectangle contained rectilineal figure regular polygon respectively rhombus right angles Schools Second Edition segment similar Similarly squares on AC straight line drawn straight line joining tangent THEOREM TRIGONOMETRY twice rectangle twice the squares vertex