Euclidian Geometry |
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Resultat 1-5 av 43
Side 13
... RIGHT ANGLES . DEFINITION . When one straight line , STRAIGHT LINES , ANGLES AND TRIANGLES . 13 PROBLEM C. ...
... RIGHT ANGLES . DEFINITION . When one straight line , STRAIGHT LINES , ANGLES AND TRIANGLES . 13 PROBLEM C. ...
Side 14
Francis Cuthbertson (M.A.). RIGHT ANGLES . DEFINITION . When one straight line , standing on another straight line , makes the adjacent angles equal to one another , each of them is called a right angle ; and the straight line which ...
Francis Cuthbertson (M.A.). RIGHT ANGLES . DEFINITION . When one straight line , standing on another straight line , makes the adjacent angles equal to one another , each of them is called a right angle ; and the straight line which ...
Side 15
... angles . if an angle one of its adjacent angles it is also the = = ..if one straight line is 1 to another , the latter is 1 to the former . Thus each of the arms of a right is 1 to the other . PROPOSITION VII . It is always possible to draw ...
... angles . if an angle one of its adjacent angles it is also the = = ..if one straight line is 1 to another , the latter is 1 to the former . Thus each of the arms of a right is 1 to the other . PROPOSITION VII . It is always possible to draw ...
Side 16
... . · DA is = EA , DF = EF , and AF common to the two AS DAF , EAF .. these as are equal in all respects ; ..L DAF is = LEAF , .. AF is to BC . ( I. 5 ) ( Def . ) " PROPOSITION VIII . From a given point in a given 16 RIGHT ANGLES .
... . · DA is = EA , DF = EF , and AF common to the two AS DAF , EAF .. these as are equal in all respects ; ..L DAF is = LEAF , .. AF is to BC . ( I. 5 ) ( Def . ) " PROPOSITION VIII . From a given point in a given 16 RIGHT ANGLES .
Side 17
... right angles are equal to one another . B CH К Let ABC , GHK be two right angles , and let the △ ABC be applied to the △ GHK , so that B may fall on H , and BC along HK , then will BA fall along HG . For if it fell in any other ...
... right angles are equal to one another . B CH К Let ABC , GHK be two right angles , and let the △ ABC be applied to the △ GHK , so that B may fall on H , and BC along HK , then will BA fall along HG . For if it fell in any other ...
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Algebra base Cambridge centre chord circumference cloth Conic Sections Crown 8vo Describe a circle diagonals diameter divided draw a straight ELEMENTARY TREATISE English equiangular equilateral Euclid Extra fcap fcap GEOMETRY given angle given circle given point given straight line Grammar greater H Let Hence inscribed intersecting isosceles triangle Latin Let ABC line bisecting locus Mathematical meet opposite angles Owens College parallel parallelogram perimeter perpendicular plane polygon PROBLEM produced Professor proportional PROPOSITION ratio rect rectangle rectangle contained rectilineal figure regular polygon respectively rhombus right angles Schools Second Edition segment similar Similarly squares on AC straight line drawn straight line joining tangent THEOREM TRIGONOMETRY twice rectangle twice the squares vertex