Euclidian Geometry |
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Resultat 1-5 av 53
Side 45
... opposite to these are right 4 s . ( 1.26 ) DEFINITION . A rectangle is a right - angled parallelogram , and is said to be contained by any two of its adjacent sides . DEFINITION . A square is a four - sided figure QUADRILATERALS . 45.
... opposite to these are right 4 s . ( 1.26 ) DEFINITION . A rectangle is a right - angled parallelogram , and is said to be contained by any two of its adjacent sides . DEFINITION . A square is a four - sided figure QUADRILATERALS . 45.
Side 46
... square . Let ABCD be the rectangle contained by AB , AD , and let AB be = AD . Then ABCD is a square . For since ABCD is a □ , .. AD is = BC , ( 1. 26 ) and AB is = DC , ( I. 26 ) also , by hypothesis , AB is = AD ; .. ABCD is ...
... square . Let ABCD be the rectangle contained by AB , AD , and let AB be = AD . Then ABCD is a square . For since ABCD is a □ , .. AD is = BC , ( 1. 26 ) and AB is = DC , ( I. 26 ) also , by hypothesis , AB is = AD ; .. ABCD is ...
Side 50
... and ... AB is divided into five equal parts . ( I. 26 ) In like manner may a straight line be divided into any given number of equal parts . PROBLEM K. Describe a square on a given straight line 50 QUADRILATERALS AND MULTILATERALS .
... and ... AB is divided into five equal parts . ( I. 26 ) In like manner may a straight line be divided into any given number of equal parts . PROBLEM K. Describe a square on a given straight line 50 QUADRILATERALS AND MULTILATERALS .
Side 51
... square on AB . Through A draw AC 1 to AB , from AC cut off AH = AB . Through H draw HK || to AB , and through B draw BK || to AH . Then ABKH shall be the square required . For , by construction , AK is a □ . .. AB is HK , = ( 1. 26 ) ...
... square on AB . Through A draw AC 1 to AB , from AC cut off AH = AB . Through H draw HK || to AB , and through B draw BK || to AH . Then ABKH shall be the square required . For , by construction , AK is a □ . .. AB is HK , = ( 1. 26 ) ...
Side 57
... square on the side oppo- site the right be equal to PF , RK . Through R draw RC Il to PH ; join RH , SQ . Now the ... square on PR . Similarly it may be proved that the QC is = the square on RQ ; ..the whole figure PHNQ , that is the ...
... square on the side oppo- site the right be equal to PF , RK . Through R draw RC Il to PH ; join RH , SQ . Now the ... square on PR . Similarly it may be proved that the QC is = the square on RQ ; ..the whole figure PHNQ , that is the ...
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Algebra base Cambridge centre chord circumference cloth Conic Sections Crown 8vo Describe a circle diagonals diameter divided draw a straight ELEMENTARY TREATISE English equiangular equilateral Euclid Extra fcap fcap GEOMETRY given angle given circle given point given straight line Grammar greater H Let Hence inscribed intersecting isosceles triangle Latin Let ABC line bisecting locus Mathematical meet opposite angles Owens College parallel parallelogram perimeter perpendicular plane polygon PROBLEM produced Professor proportional PROPOSITION ratio rect rectangle rectangle contained rectilineal figure regular polygon respectively rhombus right angles Schools Second Edition segment similar Similarly squares on AC straight line drawn straight line joining tangent THEOREM TRIGONOMETRY twice rectangle twice the squares vertex