Elementary applied mechanics, by T. Alexander (and A.W. Thomson). |
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Side 6
... stretched to double its original length or compressed to nothing , then from the definition strain unity . Examples . In the following questions the weight of the material is neglected . 1. A tie rod in a roof , whose length is 142 feet ...
... stretched to double its original length or compressed to nothing , then from the definition strain unity . Examples . In the following questions the weight of the material is neglected . 1. A tie rod in a roof , whose length is 142 feet ...
Side 7
... stretched to 101 inches . What is the strain upon it ? strain 10 = ' 025 . 10. An indiarubber string 6 inches in length is stretched till it is a foot long . Find the strain . strain = 1 . 11. A cast - iron pillar bears a strain of 001 ...
... stretched to 101 inches . What is the strain upon it ? strain 10 = ' 025 . 10. An indiarubber string 6 inches in length is stretched till it is a foot long . Find the strain . strain = 1 . 11. A cast - iron pillar bears a strain of 001 ...
Side 8
... stretched as before 1 inch by a weight of 680 lbs . , while the iron one is only stretched a 13th part of an inch by 680 lbs . Hence the elasticities of different substances are propor- tional to the stresses applied , and inversely ...
... stretched as before 1 inch by a weight of 680 lbs . , while the iron one is only stretched a 13th part of an inch by 680 lbs . Hence the elasticities of different substances are propor- tional to the stresses applied , and inversely ...
Side 10
... stretched ths of an inch . Find the intensity of the stress , the strain , and modulus of elasticity . total stress area aug . of length stress = = 32,000 lbs . 2 sq . in . = 16,000 lbs . per sq . in . .75 in . strain = ' 000625 ...
... stretched ths of an inch . Find the intensity of the stress , the strain , and modulus of elasticity . total stress area aug . of length stress = = 32,000 lbs . 2 sq . in . = 16,000 lbs . per sq . in . .75 in . strain = ' 000625 ...
Side 11
... stretched by a weight of one ton ? total stress = 2240 lbs . stress = total stress in lbs . area in sq . in . 2240 ÷ 1 = 17,920 lbs . per sq . inch . stress E = strain stress .. strain = E 17,920 = 000512 . 35,000,000 elongation length ...
... stretched by a weight of one ton ? total stress = 2240 lbs . stress = total stress in lbs . area in sq . in . 2240 ÷ 1 = 17,920 lbs . per sq . inch . stress E = strain stress .. strain = E 17,920 = 000512 . 35,000,000 elongation length ...
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amount of resilience amount of stress angle of repose augmentation axis Cambridge chain component stresses cos² Crown 8vo dead load direction and intensity earth Edition ellipse elongation equal Equating equilibrium Eton College Extra fcap feet long find the intensity find the stress ft.-lbs greater greatest principal stress Hence Hooke's law horizontal inch in section instant internal stress J. P. MAHAFFY LATIN layer length live load modulus of elasticity normal component OM² Owens College pair of rectangular parallelopiped plane BB plane inclined plane of greatest planes of principal position of cc principal stresses Professor proof strain proof stress rectangular planes right angles School shearing shearing stress sin² sloping solid square inch stress on cc stretched surface tangential component tangential stress thrust total stress velocity wall weight
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