Elementary applied mechanics, by T. Alexander (and A.W. Thomson). |
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Resultat 1-5 av 24
Side 10
... tension of 32,000 lbs , by which it is stretched ths of an inch . Find the intensity of the stress , the strain , and modulus of elasticity . total stress stress = = strain = area aug . of length length 32,000 lbs . 2 sq . in . = 16,000 ...
... tension of 32,000 lbs , by which it is stretched ths of an inch . Find the intensity of the stress , the strain , and modulus of elasticity . total stress stress = = strain = area aug . of length length 32,000 lbs . 2 sq . in . = 16,000 ...
Side 20
... 10 feet long and 5 of a square inch in section , is kept at the proof strain by a tension of 25,000 lbs . , the modulus of elasticity for steel being 35,000,000 . Find the resilience of steel , also the amount of 20 APPLIED MECHANICS .
... 10 feet long and 5 of a square inch in section , is kept at the proof strain by a tension of 25,000 lbs . , the modulus of elasticity for steel being 35,000,000 . Find the resilience of steel , also the amount of 20 APPLIED MECHANICS .
Side 22
... tension of 600 lbs . on the square inch is admitted suddenly upon a piston 18 inches in diameter . If the piston rod be two inches in diameter and 7 feet long , what is the amount of its resilience at 22 APPLIED MECHANICS .
... tension of 600 lbs . on the square inch is admitted suddenly upon a piston 18 inches in diameter . If the piston rod be two inches in diameter and 7 feet long , what is the amount of its resilience at 22 APPLIED MECHANICS .
Side 23
... moving a signal 600 yards distant has , when the signal is down , a tension upon it of 250 lbs . , which is maintained by the back weight of the hand lever ; under the circumstances the wire is stretched 1.44 feet ( see RESILIENCE . 23.
... moving a signal 600 yards distant has , when the signal is down , a tension upon it of 250 lbs . , which is maintained by the back weight of the hand lever ; under the circumstances the wire is stretched 1.44 feet ( see RESILIENCE . 23.
Side 24
... tension on the wire the instant the lever is put back will be that due to an elongation of ( 1.44 + 373 ) ft . = 1.44 +373 1:44 250 lbs . = 314.8 lbs . This is the force which must be exerted at the point where the wire is attached to ...
... tension on the wire the instant the lever is put back will be that due to an elongation of ( 1.44 + 373 ) ft . = 1.44 +373 1:44 250 lbs . = 314.8 lbs . This is the force which must be exerted at the point where the wire is attached to ...
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amount of resilience amount of stress angle of repose augmentation axis Cambridge chain component stresses cos² cos²y Crown 8vo dead load direction and intensity earth Edition ellipse entirely tangential equal Equating equilibrium Eton College Extra fcap feet long find the stress ft.-lbs greater greatest principal stress Hence Hooke's law horizontal inch in section instant internal stress J. P. MAHAFFY LATIN layer length live load modulus of elasticity normal component OM² OR² pair of rectangular parallelopiped plane BB plane inclined plane of greatest planes of principal principal stresses Professor proof strain proof stress rectangular planes revised right angles School shearing shearing stress sin² sloping solid square inch stress on cc stretched surface tangential component tangential stress thrust total stress Trinity College velocity wall weight x₁
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