Plane and Solid GeometryGinn, 1903 - 473 sider |
Inni boken
Resultat 1-5 av 67
Side 10
... adjacent angles when they have the same vertex and a com- mon side between them ; as the angles BOD Ā and AOD ( Fig . 10 ) . D B FIG . 10 . 63. When one straight line meets another straight line and 10 BOOK I. PLANE GEOMETRY .
... adjacent angles when they have the same vertex and a com- mon side between them ; as the angles BOD Ā and AOD ( Fig . 10 ) . D B FIG . 10 . 63. When one straight line meets another straight line and 10 BOOK I. PLANE GEOMETRY .
Side 11
... meets another line is called the foot of the perpendicular . 66. When the sides of an angle extend in opposite directions , so as to be in the same straight line , the angle is called a straight angle . A ← C FIG . 12 . B Thus , the ...
... meets another line is called the foot of the perpendicular . 66. When the sides of an angle extend in opposite directions , so as to be in the same straight line , the angle is called a straight angle . A ← C FIG . 12 . B Thus , the ...
Side 22
... meet the line CB at E. Then and CA + CE > OA + OE , BE + OE > OB , ( a straight line is the shortest line from one point to another ) . Add these inequalities , and we have CA + CE + BE + OE > OA + OE + OB . Substitute for CE + BE its ...
... meet the line CB at E. Then and CA + CE > OA + OE , BE + OE > OB , ( a straight line is the shortest line from one point to another ) . Add these inequalities , and we have CA + CE + BE + OE > OA + OE + OB . Substitute for CE + BE its ...
Side 24
... meet however far they are produced . PROPOSITION X. THEOREM . 104. Two straight lines in the same plane perpen- dicular to the same straight line are parallel . A C -B D Let AB and CD be perpendicular to AC . To prove that AB and CD are ...
... meet however far they are produced . PROPOSITION X. THEOREM . 104. Two straight lines in the same plane perpen- dicular to the same straight line are parallel . A C -B D Let AB and CD be perpendicular to AC . To prove that AB and CD are ...
Side 65
... meet it at G. A DE is to BC if BCGD is a . § 166 D E G BCGD is a if CG = BD . § 183 CG = BD if each is equal to AD . Ax . 1 B Now = BD AD . Hyp . And But For CG AD if △ CGE = △ ADE . ACGEA ADE . EC AE . = LGECLAED . LECGLDAE . $ 128 ...
... meet it at G. A DE is to BC if BCGD is a . § 166 D E G BCGD is a if CG = BD . § 183 CG = BD if each is equal to AD . Ax . 1 B Now = BD AD . Hyp . And But For CG AD if △ CGE = △ ADE . ACGEA ADE . EC AE . = LGECLAED . LECGLDAE . $ 128 ...
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AB² ABCDE AC² altitude apothem axis bisector bisects called centre chord circumference circumscribed coincide common construct curve denote diagonals diameter dihedral angles distance divided draw ellipse equidistant equilateral triangle equivalent face angles feet Find the area Find the locus frustum given circle given line given point given straight line given triangle greater Hence homologous homologous sides hypotenuse inches intersection lateral area lateral edges length limit middle point number of sides parallel planes parallelogram parallelopiped perimeter perpendicular plane MN polyhedral angle polyhedron prism prismatoid Proof prove Q. E. D. PROPOSITION radii radius ratio rectangle regular polygon regular pyramid respectively right angle right circular right triangle secant segments similar slant height sphere spherical polygon spherical triangle square surface tangent tetrahedron THEOREM trapezoid triangle ABC triangular prism trihedral vertex vertices