Queen's scholarship examination. Amner's eight years' scholarship questions ... in Euclid, algebra, & mensuration1879 |
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Resultat 1-5 av 14
Side 17
Joseph Wollman. MENSURATION . 5. Find the acreage of a field which has two ... Area of parallelogram ABED Area of triangle DEC = BE X DF = ( 250 × 80 ) ... radius of which is 144 feet ? Radius = 144 feet . .. Diameter = 288 feet ...
Joseph Wollman. MENSURATION . 5. Find the acreage of a field which has two ... Area of parallelogram ABED Area of triangle DEC = BE X DF = ( 250 × 80 ) ... radius of which is 144 feet ? Radius = 144 feet . .. Diameter = 288 feet ...
Side 25
... Then 4x = elder . " " 3 Multiplying each side by 6 Transposing 4-9-3 ( x - 9 ) } 8x549x - 81 } 8x 9x = 54-81 -x = - -27 ..x = 27 age of the younger , 4x and = = 36 ,, elder . 22 3 MENSURATION . SECTION V. 1. Find the area in acres 25.
... Then 4x = elder . " " 3 Multiplying each side by 6 Transposing 4-9-3 ( x - 9 ) } 8x549x - 81 } 8x 9x = 54-81 -x = - -27 ..x = 27 age of the younger , 4x and = = 36 ,, elder . 22 3 MENSURATION . SECTION V. 1. Find the area in acres 25.
Side 26
... Find the diagonal of a square that shall be equal in area to a rectangle of which two adjacent sides are 30 and 20 . Area of rectangle Side of square = = 30 x 20 = = 600 = √600 .. Diagonal of square = √ ( √600 ) 2 + √ ( 600 ) 2 ...
... Find the diagonal of a square that shall be equal in area to a rectangle of which two adjacent sides are 30 and 20 . Area of rectangle Side of square = = 30 x 20 = = 600 = √600 .. Diagonal of square = √ ( √600 ) 2 + √ ( 600 ) 2 ...
Side 40
... find its length and breadth . Let x = the breadth of the garden in yards Then +50 = length : .x ( x + 50 ) = area : .x ( x + 50 ) = 9375 x2 + 50x = 9375 Completing the square Extracting the square root 99 " 9 29 99 } x2 + 50x + ( 25 ) 2 ...
... find its length and breadth . Let x = the breadth of the garden in yards Then +50 = length : .x ( x + 50 ) = area : .x ( x + 50 ) = 9375 x2 + 50x = 9375 Completing the square Extracting the square root 99 " 9 29 99 } x2 + 50x + ( 25 ) 2 ...
Side 42
... Area of garden plot = ( 75 × 50 ) sq . ft . = 3750 sq . ft . وو " " circular beds = 4 ( 62 × .7854 ) = 99 = 4 ( 36 x ... find the letting price per acre . B Perpendicular AD = √AB2 - BD2 500 800 90000 = = √5002 - 4002 = √250000 - 16000 = ...
... Area of garden plot = ( 75 × 50 ) sq . ft . = 3750 sq . ft . وو " " circular beds = 4 ( 62 × .7854 ) = 99 = 4 ( 36 x ... find the letting price per acre . B Perpendicular AD = √AB2 - BD2 500 800 90000 = = √5002 - 4002 = √250000 - 16000 = ...
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Queen's Scholarship Examination. Amner's Eight Years' Scholarship Questions ... Joseph Wollman Ingen forhåndsvisning tilgjengelig - 2015 |
Vanlige uttrykk og setninger
2ax² a²b a²x a²x² ABCD AC.CB acres acute angle ALGEBRA angle ABC angle AEB angle BAC ax² bisected breadth centre circle circumference co-efficient Completing the square diameter Dividing each side equal bases EUCLID factor find the area Find the G.C.M. four times sq given line given point given squares given straight line given triangle greater half the square hypotenuse inches isosceles triangle LONDON SCHOOL BOARD MENSURATION miles Multiplying each side Notes of Lessons number represented opposite angles parallelogram perpendicular proposition prove Pupil Teachers quadrilateral Queen's Scholarship rectangle contained rectangle HK rhombus right angles right-angled triangle Scholarship Examination SECTION Show square Extracting square on GH square root squares described triangle ABC triangle EOD triangle RMN twice rect twice the rectangle unequal x²y yards
Populære avsnitt
Side 64 - If a straight line touch a circle, and from the point of contact a straight line be drawn cutting the circle, the angles which this line makes with the line touching the circle shall be equal to the angles which are in the alternate segments of the circle.
Side 80 - To make a triangle of which the sides shall be equal to three given straight lines, but any two whatever of these must be greater than the third (20.
Side 60 - A circle is a plane figure contained by one line, which is called the circumference, and is such, that all straight lines drawn from a certain point within the figure to the circumference are equal to one another : 16. And this point is called the centre of the circle.
Side 48 - ... the sides containing the obtuse angle, by twice the rectangle contained by the side upon which, when produced, the perpendicular falls, and the straight line intercepted without the triangle between the perpendicular and the obtuse...
Side 82 - If, at a point in a straight line, two other straight lines, upon the opposite sides of it, make the adjacent angles together equal to two right angles, these two straight lines shall be in one and the same straight line.
Side 60 - IF two straight lines cut one another, the vertical, or opposite, angles shall be equal.
Side 45 - Straight lines which are parallel to the same straight line are parallel to one another. Triangles and Rectilinear Figures. The sum of the angles of a triangle is equal to two right angles.
Side 32 - If a straight line be divided into two equal parts, and also into two unequal parts ; the rectangle contained by the unequal parts, together with the square on the line between the points of section, is equal to the square on half the line.
Side 13 - If two angles of a triangle be equal to one another, the sides also which subtend, or are opposite to, the equal angles, shall be equal to one another.
Side 30 - All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides.