Trigonometry, Plane and Spherical;: With the Construction and Application of Logarithms |
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Resultat 1-5 av 5
Side 15
COROLLARY I. ( PGEBE ) DGBE ) Because of the foregoing proportions , we
have ' DG + BE OmxCF DG - BE , and Du OC Dmx FO 2 Om x CF ; and therefore
DG + BEOC OC 2DmxFO and DG — BE = OC COROLLARY II . Hence , if the
mean ...
COROLLARY I. ( PGEBE ) DGBE ) Because of the foregoing proportions , we
have ' DG + BE OmxCF DG - BE , and Du OC Dmx FO 2 Om x CF ; and therefore
DG + BEOC OC 2DmxFO and DG — BE = OC COROLLARY II . Hence , if the
mean ...
Side 29
E. D. COROLLARY . Hence , in right - angled spherical triangles ABC , CBD ,
having the same perpendicular BC ( see the last figure ) , the co - fines of the
angles at the base will be to each other , directly , as the fines of the vertical
angles : For ...
E. D. COROLLARY . Hence , in right - angled spherical triangles ABC , CBD ,
having the same perpendicular BC ( see the last figure ) , the co - fines of the
angles at the base will be to each other , directly , as the fines of the vertical
angles : For ...
Side 55
E. I. 1 COROLLARY I. Hence , if the fines of two arches be denoted by S and s ;
their co - fines by C and c ; and radius by R ; then will the fine of their sum Sc +
SC R SC SC the sine of their difference = R the co - fine of their sum = CCSS R
the ...
E. I. 1 COROLLARY I. Hence , if the fines of two arches be denoted by S and s ;
their co - fines by C and c ; and radius by R ; then will the fine of their sum Sc +
SC R SC SC the sine of their difference = R the co - fine of their sum = CCSS R
the ...
Side 56
COROLLARY II . fine = Hence , the line of the double of either arch 2CS ( when
they are equal ) will be = and its coR C ' - SP : whence it appears , that the fine of
R the double of any arch , is equal to twice the rečtangle of the fine and co - fine ...
COROLLARY II . fine = Hence , the line of the double of either arch 2CS ( when
they are equal ) will be = and its coR C ' - SP : whence it appears , that the fine of
R the double of any arch , is equal to twice the rečtangle of the fine and co - fine ...
Side 78
COROLLARY 1 . Hence , because IR X V is = the square of the sine of C ( by
Prop . 1. ) it follows that fq . S. ; C = R ? X S. ŽAB + AF X S. ZAB - AF S. AC X S.
BC From whence we have the following theorem , for solving the 11th case of
oblique ...
COROLLARY 1 . Hence , because IR X V is = the square of the sine of C ( by
Prop . 1. ) it follows that fq . S. ; C = R ? X S. ŽAB + AF X S. ZAB - AF S. AC X S.
BC From whence we have the following theorem , for solving the 11th case of
oblique ...
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Trigonometry, Plane and Spherical: With the Construction and Application of ... Thomas Simpson Uten tilgangsbegrensning - 1799 |
Vanlige uttrykk og setninger
added alſo appears arch balf baſe becauſe called caſe chord circle co-f co-fine AC co-tang common complement conſequently Corol COROLLARY determine diameter difference divided drawn equal equal to half evident exceſs extremes fide AC fine fines firſt follows given gives gles greater half the ſum half their difference Hence hyperbolic logarithm hypothenuſe laſt logarithm manifeft meeting method minute moreover Note oppoſite parallel perpendicular plane triangle ABC preceding progreſſion PROP proportion propoſed radius rectangle reſpectively right-angled ſame ſecant ſee ſeries ſhall ſides ſince ſine ſpherical Spherical triangle ABC ſubtracted ſum ſuppoſed tang tangent of half Tbeor Theor THEOREM thereof theſe thoſe unity verſed vertical angle whence