## Trigonometry, Plane and Spherical;: With the Construction and Application of Logarithms |

### Inni boken

Resultat 1-5 av 5

Side 11

Ill . ) Two sides ( The other As sum of AB and AC : their AC , AB and angles Cdif .

:: tang . of

angle A diff . ( by Theor . V. ) which added to , and subtracted from , the half fum ...

Ill . ) Two sides ( The other As sum of AB and AC : their AC , AB and angles Cdif .

:: tang . of

**half the sum**of the included and ABC ABC and C : tang . of half their 4angle A diff . ( by Theor . V. ) which added to , and subtracted from , the half fum ...

Side 30

E. D. LE M M A. As the sum of the fines of two unequat arches is to their

difference , so is the tangent of

their difference : and , as the sum of the co - lines is to their difference , so is the

co ...

E. D. LE M M A. As the sum of the fines of two unequat arches is to their

difference , so is the tangent of

**half the Sum**of those arches to the tangent of halftheir difference : and , as the sum of the co - lines is to their difference , so is the

co ...

Side 56

... CD ( BC ) is equal to a rectangle under

the co - fines , of the

of their co - fines is equal to a re tangle under

co ...

... CD ( BC ) is equal to a rectangle under

**half**the radius , and the difference ofthe co - fines , of the

**sum**and difference of those arches ; and that the rectangleof their co - fines is equal to a re tangle under

**half**the radius , and the**sum**of theco ...

Side 61

and , consequently ,

Moreover , seeing DCB is = the

1. ) it is evident that BCF ( or DCF ) is equal to

ECF is ...

and , consequently ,

**half**the vertical angle ACB = D + CBD ( by 9. 1. ) = D.Moreover , seeing DCB is = the

**sum**of the angles A and CBA , at the base ( by 9.1. ) it is evident that BCF ( or DCF ) is equal to

**half**that**sum**; and , therefore , asECF is ...

Side 62

It is B manifest , because CD = CB , that CDB and CBD are equal to one another ,

and that each of them is also equal to

base ( by Cor . 2. to 10. 1. ) ; therefore ABD , being the excess of the greater ...

It is B manifest , because CD = CB , that CDB and CBD are equal to one another ,

and that each of them is also equal to

**half the sum**of the angles CBA and A at thebase ( by Cor . 2. to 10. 1. ) ; therefore ABD , being the excess of the greater ...

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### Vanlige uttrykk og setninger

added alſo appears arch balf baſe becauſe called caſe chord circle co-f co-fine AC co-tang common complement conſequently Corol COROLLARY determine diameter difference divided drawn equal equal to half evident exceſs extremes fide AC fine fines firſt follows given gives gles greater half the ſum half their difference Hence hyperbolic logarithm hypothenuſe laſt logarithm manifeft meeting method minute moreover Note oppoſite parallel perpendicular plane triangle ABC preceding progreſſion PROP proportion propoſed radius rectangle reſpectively right-angled ſame ſecant ſee ſeries ſhall ſides ſince ſine ſpherical Spherical triangle ABC ſubtracted ſum ſuppoſed tang tangent of half Tbeor Theor THEOREM thereof theſe thoſe unity verſed vertical angle whence