Trigonometry, Plane and Spherical;: With the Construction and Application of Logarithms |
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Resultat 1-5 av 6
Side 24
It follows moreover , that the periphery of a great - circle is every where 90
degrees distant from its pole ; and that the B A measure of a spherical angle CAD
* is an arch of a great circle intercepted by the two circles ACB , ADB forming that
...
It follows moreover , that the periphery of a great - circle is every where 90
degrees distant from its pole ; and that the B A measure of a spherical angle CAD
* is an arch of a great circle intercepted by the two circles ACB , ADB forming that
...
Side 26
Moreover , since both the planes OIK and AIK are perpendicular to the plane of
the base ( or paper ) ; their intersection IK will also be perpendicular to it , and
consequently the angle AIK a right - angle . Therefore , seeing the angles OFE ,
GHC ...
Moreover , since both the planes OIK and AIK are perpendicular to the plane of
the base ( or paper ) ; their intersection IK will also be perpendicular to it , and
consequently the angle AIK a right - angle . Therefore , seeing the angles OFE ,
GHC ...
Side 52
AB = 14611 - 4,1646800 Moreover , in the oblique plane triangle ABC , let chere
be given AB = 75 , AC = 60 , and the included angle A = 48 ° ; to find the other
two angles . Then ( by Tbeorem 5. ) it will be , A B As AB + AC ( 135 ) its log .
AB = 14611 - 4,1646800 Moreover , in the oblique plane triangle ABC , let chere
be given AB = 75 , AC = 60 , and the included angle A = 48 ° ; to find the other
two angles . Then ( by Tbeorem 5. ) it will be , A B As AB + AC ( 135 ) its log .
Side 56
Moreover , because Dm X CF = OC X mv ( LOC REG = 40C OE - OG ) ; and Om *
OF = OC X On ( LOC X 2On = OC X OE + OG ) , it follows , that the rectangle of
the fines of any two arches ( AC , CD ( BC ) is equal to a rectangle under half the
...
Moreover , because Dm X CF = OC X mv ( LOC REG = 40C OE - OG ) ; and Om *
OF = OC X On ( LOC X 2On = OC X OE + OG ) , it follows , that the rectangle of
the fines of any two arches ( AC , CD ( BC ) is equal to a rectangle under half the
...
Side 63
D C 1 Let ABCD be a circle described about the triangle , and from 0 , the center
thereof , let OB and OC be drawn ; moreover , draw CD parallel to BA , meeting
the periphery in D , and EOF , perpendicular to AB , meeting DC in E. Then it is ...
D C 1 Let ABCD be a circle described about the triangle , and from 0 , the center
thereof , let OB and OC be drawn ; moreover , draw CD parallel to BA , meeting
the periphery in D , and EOF , perpendicular to AB , meeting DC in E. Then it is ...
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Trigonometry, Plane and Spherical: With the Construction and Application of ... Thomas Simpson Uten tilgangsbegrensning - 1799 |
Vanlige uttrykk og setninger
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