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gles, each to each, to which the equal fides are oppofite. there- Book I. fore the angle ACB is equal to the angle CBD. and because then ftraight line BC meets the two straight lines AC, BD and makes b. 4. 1. the alternate angles ACB, CBD equal to one another, AC is pa

rallel to BD. and it was fhewn to be equal to it. therefore c. 17. I. ftraight lines, &c. Q. E. D.

THE

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HE oppofite fides and angles of parallelograms are equal to one another, and the diameter bisects them, that is, divides them into two equal parts.

N. B. A Parallelogram is a four fided figure of which the oppofite fides are parallel. and the diameter is the ftraight line joining two of its oppofite angles.

Let ABCD be a parallelogram, of which BC is a diameter. the oppofite fides and angles of the figure are equal to one another; and the diameter BC bifects it.

a

A

B

Because AB is parallel to CD, and BC meets them, the alternate angles ABC, BCD are equal to one another, and because AC is parallel to BD, and BC meets them, the alternate angles ACB, CBD are equal to one another. wherefore the two triangles ABC, CBD have two angles ABC, BCA

a

C

D

a. 29. T.

in one, equal to two angles BCD, CBD in the other, each to each, and one fide BC common to the two triangles, which is adjacent to their equal angles; therefore their other fides fhall be equal, each to each, and the third angle of the one to the third angle of the other, viz. the fide AB to the fide CD, and AC to BD, and b. 26. 1. the angle BAC equal to the angle BDC. and because the angle ABC is equal to the angle BCD, and the angle CPD to the angle ACB; the whole angle ABD is equal to the whole angle ACD. and the angle BAC has been fhewn to be equal to the angle BDC; therefore the opposite fides and angles of parallelograms are equal to one another. alfo, their diameter bifects them. for, AB being equal to CD, and BC common; the two AB, BC are equal to the two DC, CB, each to each; and the angle ABC is equal to the

c

Book I. angle BCD; therefore the triangle ABC is equal to the triangle BCD, and the diameter BC divides the parallelogram ACDB into two equal parts. Q. E. D.

See N.

1.

See the

ad and 3d Figures.

a. 34. I.

PROP. XXXV. THEOR.

PARALLELOGRAMS upon the same base and between

the fame parallels, are equal to one another.

Let the parallelograms ABCD, EBCF be upon the fame base BC and between the fame parallels AF, BC. the parallelogiam ABCD fhall be equal to the parallelogram EBCF.

If the fides AD, DF of the parallelograms ABCD, DBCF oppofite to the bafe BC, be terminated in the fame point D; it is plain that each

of the parallelograms is double of the A

triangle BDC; and they are therefore
equal to one another.

Butif the fides AD, EF oppofite to the
bafe BC of the parallelograms ABCD,
EBCF be not terminated in the fame B

D

F

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point; then because ABCD is a parallelogram, AD is equal 1 t☛ BC; for the fame reafon, EF is equal to BC; wherefore AD is equal to EF; and DE is common; therefore the whole, or the e. 2. or 3. remainder, AE is equal to the whole, or the remainder DF; AB alfo is equal to DC; and the two EA, AB are therefore equal

b. 1. Ax.

Ax

d. 29. 1.

C. 4. 1.

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c

FAED F

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B

C

B

e

to the two FD, DC, each to each; and the exterior angle FDC is equal to the interior EAB; therefore the bafe EB is equal to the bafe FC, and the triangle EAB equal to the triangle FDC. take the triangle FDC from the trapezium ABCF, and from the fame trapezium take the triangle EAB; the remainders therefore are f. 3. Ax. equalf, that is, the parallelogram ABCD is equal to the parallelogram EBCF. therefore parallelograms upon the fame bafe, &c. Q.ED.

PROP. XXXVI. THEOR.

PARALLELOGRAMS upon equal bafes and between

the fame parallels, are equal to one another.

Let ABCD, EFGH be parallelograms upon equal bafes BC, FG,

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Book I.

a. 34. 2.

are parallels, and joined towards the fame parts by the straight lines BE, CH. but straight lines which join equal and parallel ftraight lines towards the fame parts, are themselves equal and parallel ; therefore EB, CH are both equal and parallel, and b. 33. г. EBCH is a parallelogram; and it is equal to ABCD, because it. 35. 3. is upon the fame bafe BC, and between the fame parallels BC, AD. for the like reafon the parallelogram EFGH is equal to the fame EBCH. therefore alfo the parallelogram ABCD is equal to EFGH. Wherefore parallelograms, &c. Q. E. D.

TRI

PROP. XXXVII. THEOR.

RIANGLES upon the fame bafe, and between the
fame parallels, are equal to one another.

Let the triangles ABC, DBC be upon the fame bafe BC and between the fame parallels

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AD

C

F

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figures EBCA, DBCF is a parallelogram; and EBCA is equal b tob. 35. x, DBCF, because they are upon the fame bafe BC, and between the fame parallels BC, EF; and the triangle ABC is the half of the paz C

c

Book I. rallelogram EBCA, because the diameter AB bifects it; and the triangle DBC is the half of the parallelogram DBCF, because the diameter DC bifects it. but the halves of equal things are equal; therefore the triangle ABC is equal to the triangle DBC. Wherefore triangles, &c. Q. E. D.

C. 34. I. d. 7. Ax.

2. 31. I.

b. 36. 1.

TRI

PROP. XXXVIII. THEOR.

RIANGLES upon equal bafes, and between the fame parallels, are equal to one another.

Let the triangles ABC, DEF be upon equal bafes BC, EF, and between the fame parallels BF, AD. the triangle ABC is equal to the triangle DEF.

a

A

D

H

Produce AD both ways to the points G, H, and thro' B draw BG parallel to CA, and thro' F draw FH parallel to ED. then each of the figures G GBCA, DEFH is a parallelogram; and they are equal b to one another, because they are upon equal bafes BC, EF and be

tween the fame paral

B

CE

C. 34. I.

lels BF, GH; and the triangle ABC is the half of the parallelogram GBCA, because the diameter AB bifects it; and the triangle DEF is the half of the parallelogram DEFH, because the diameter DF bifects it. but the halves of equal things are d. 7. Ax. equal; therefore the triangle ABC is equal to the triangle DEF. Wherefore triangles, &c. Q. E. D.

2. 31. I.

PROP. XXXIX. THEOR.

EQUAL triangles upon the fame bafe, and upon the

fame fide of it, are between the fame parallels.

Let the equal triangles ABC, DBC be upon the fame base BC, and upon the fame fide of it; they are between the fame parallels. Join AD; AD is parallel to BC; for if it is not, thro' the point A draw AE parallel to BC, and join EC. the triangle ABC is

35

equal to the triangle EBC, because it is upon the fame bafe BC, Book I. and between the fame parallels BC, AE. A but the triangle ABC is equal to the tri

E

D

b. 37. 1.

angle BDC; therefore alfo the triangle

BDC is equal to the triangle EBC, the

greater to the lefs, which is impoffible.
therefore AE is not parallel to BC. in
the fame manner it can be demonftrated B

that no other line but AD is parallel to BC; AD is therefore pa-
rallel to it. Wherefore equal triangles upon, &c. Q. E. D.

PROP. XL. THEOR.

EQUAL triangles upon equal bases, and towards the

fame parts, are between the fame parallels.

Let the equal triangles ABC, DEF be upon equal bafes BC, EF,

and towards the fame parts; they are between the fame parallels.

Join AD; AD is parallel to BC. for if it is not, thro' A draw AG parallel to BF,

a

and join GF. the triangle

ABC is equal to the triangle

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GEF, because they are upon equal bafes BC, EF, and between the fame parallels BF, AG. but the triangle ABC is equal to the triangle DEF; therefore alfo the triangle DEF is equal to the triangle GEF, the greater to the lefs, which is impoffible. therefore AG is not parallel to BF. and in the fame manner it can be demonstrated that there is no other parallel to it but AD, AD is therefore parallel to BF. Wherefore equal triangles, &c. Q. E. D.

IF

PROP. XLI. THEOR.

F a parallelogram and triangle be upon the fame bafe, and between the fame parallels; the parallelogram fhall be double of the triangle.

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