The Elements of Euclid: The Errors, by which Theon, Or Others, Have Long Ago Vitiated These Books, are Corrected and Some of Euclid's Demonstrations are Restored. Also, The Book of Euclid's Data, in Like Manner Corrected. viz. The first six books, together with the eleventh and twelfthA. Foulis, 1781 - 466 sider |
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Side 7
... Because the point A is the center of the circle BCD , AC is equal b . ad Poft . finition . * to AB . and because the point B is the center of the circle ACE , c . 15th De- BC is equal to BA . but is has been proved that CA is equal to ...
... Because the point A is the center of the circle BCD , AC is equal b . ad Poft . finition . * to AB . and because the point B is the center of the circle ACE , c . 15th De- BC is equal to BA . but is has been proved that CA is equal to ...
Side 9
... because AB is equal to DE . and AB coin- ciding with DE , AC shall coincide with DF , because the angle BAC is equal to the angle EDF . wherefore alfo the point C fhall coin- cide with the point F , because the straight line AC is equal ...
... because AB is equal to DE . and AB coin- ciding with DE , AC shall coincide with DF , because the angle BAC is equal to the angle EDF . wherefore alfo the point C fhall coin- cide with the point F , because the straight line AC is equal ...
Side 11
... because in the triangles DBC , ACB , DB is equal to AC , and BC common to both , the two fides DB , BC are equal to the two AC , CB , each to each ; and the angle DBC is equal to the angle ACB ; therefore the bafe DC is equal to the ...
... because in the triangles DBC , ACB , DB is equal to AC , and BC common to both , the two fides DB , BC are equal to the two AC , CB , each to each ; and the angle DBC is equal to the angle ACB ; therefore the bafe DC is equal to the ...
Side 19
... Because AC is greater than AB , make AD equal to AB , and join BD . and because ADB is the exterior angle of the tri- b c 2. 3. 1 angle BDC , it is greater than the interior and oppofite angle . 16 . DCB . but ADB is equal to ABD , because ...
... Because AC is greater than AB , make AD equal to AB , and join BD . and because ADB is the exterior angle of the tri- b c 2. 3. 1 angle BDC , it is greater than the interior and oppofite angle . 16 . DCB . but ADB is equal to ABD , because ...
Side 21
... because the two fides CE , ED of the triangle CED are greater than CD , add DB to each of thefe ; therefore the fides CE , EB are greater than CD , D3 . but it has been fhewn that BA , AC are greater than BE , B A E D EC ; much more ...
... because the two fides CE , ED of the triangle CED are greater than CD , add DB to each of thefe ; therefore the fides CE , EB are greater than CD , D3 . but it has been fhewn that BA , AC are greater than BE , B A E D EC ; much more ...
Andre utgaver - Vis alle
The Elements of Euclid, Viz: The Errors, by which Theon, Or Others, Have ... Robert Simson Uten tilgangsbegrensning - 1775 |
The Elements of Euclid: The Errors, by which Theon, Or Others, Have Long Ago ... Robert Simson Uten tilgangsbegrensning - 1762 |
The Elements of Euclid: The Errors by which Theon, Or Others, Have Long ... Robert Simson Uten tilgangsbegrensning - 1827 |
Vanlige uttrykk og setninger
AC is equal alfo alſo angle ABC angle BAC bafe baſe BC is given becauſe the angle bifected Book XI cafe circle ABCD circumference cone confequently cylinder defcribed demonftrated diameter drawn EFGH equal angles equiangular equimultiples Euclid excefs faid fame manner fame multiple fame ratio fecond fegment fhall fhewn fide BC fides fimilar fince firft firſt folid angle fome fore fquare of AC ftraight line AB given angle given ftraight line given in fpecies given in magnitude given in pofition given magnitude given ratio gnomon greater join lefs leſs likewife line BC muſt oppofite parallel parallelepipeds parallelogram perpendicular prifm Propofition proportionals pyramid rectangle contained rectilineal figure right angles ſhall ſphere ſquare thefe THEOR theſe thro tiple triangle ABC vertex wherefore
Populære avsnitt
Side 156 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Side 3 - A circle is a plane figure contained by one line, which is called the circumference, and is such that all straight lines drawn from a certain point within the figure to the circumference, are equal to one another.
Side 323 - Equiangular parallelograms have to one another the ratio which is compounded of the ratios of their sides.
Side 92 - If from a point without a circle there be drawn two straight lines, one of which cuts the circle, and the other meets it ; if the rectangle contained by the whole line which cuts the circle, and the part of it without the circle, be equal to the square- of the line which meets it, the line which meets shall touch the circle.
Side 80 - EA : and because AD is equal to DC, and DE common to the triangles ADE, CDE, the two sides AD, DE are equal to the two CD, DE, each to each ; and the angle ADE is equal to the angle CDE, for each of them is a right angle ; therefore the base AE is equal (4.
Side 52 - If a straight line be bisected, and produced to any point, the square of the whole line thus produced, and the square of the part of it produced, are together double of the square of half the line bisected, and of the square of the line made up of the half and the part produced.
Side 36 - To a given straight line to apply a parallelogram, which shall be equal to a given triangle, and have one of its angles equal to a given rectilineal angle.
Side 2 - When a straight line standing on another straight line makes the adjacent angles equal to one another, each of the angles is called a right angle; and the straight line which stands on the other is called a perpendicular to it.
Side 54 - AB be the given straight line ; it is required to divide it into two parts, so that the rectangle contained by the whole, and one of the parts, shall be equal to the square of the other part.
Side 74 - The straight line drawn at right angles to the diameter of a circle, from the extremity of it, falls without the circle...