The Elements of Euclid: The Errors, by which Theon, Or Others, Have Long Ago Vitiated These Books, are Corrected and Some of Euclid's Demonstrations are Restored. Also, The Book of Euclid's Data, in Like Manner Corrected. viz. The first six books, together with the eleventh and twelfth |
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Resultat 1-5 av 16
Side 67
MK , ML , MH . and because AM is equal to ME , add MD to each , therefore AD is
equal to EM , MD ; but EM , MD are greater b . 20. fi than ED , therefore also AD is
greater than ED . again , because ME is equal to MF , and MD common to the ...
MK , ML , MH . and because AM is equal to ME , add MD to each , therefore AD is
equal to EM , MD ; but EM , MD are greater b . 20. fi than ED , therefore also AD is
greater than ED . again , because ME is equal to MF , and MD common to the ...
Side 167
5 , to BL , as CD to DK , and BL is to LH , as DK to KE , because the triangles BLH
, DKE are equiangular . therefore because the five fided figures AGHLB , CFEKD
are equiangular , and have their sides about the equal angles proportionals ...
5 , to BL , as CD to DK , and BL is to LH , as DK to KE , because the triangles BLH
, DKE are equiangular . therefore because the five fided figures AGHLB , CFEKD
are equiangular , and have their sides about the equal angles proportionals ...
Side 169
Join BE , EC , GL , LH . and because the polygon ABCDE is Book VI . similar to
the polygon FGHKL , the angle BAE is equal to the angle GFL · , and BA is to AE ,
as GF tu FL ' . wherefore because a . 1. Def.6 . the triangles ABE , FGL have an ...
Join BE , EC , GL , LH . and because the polygon ABCDE is Book VI . similar to
the polygon FGHKL , the angle BAE is equal to the angle GFL · , and BA is to AE ,
as GF tu FL ' . wherefore because a . 1. Def.6 . the triangles ABE , FGL have an ...
Side 184
Join BC , CK , and in the circumferences BC , CK take any points X , O , and join
BX , XC , CO , OK . then because in the triangles GBC , GCK the iwo sides BG ,
GC are equal to the two CG , GK , and that they contain equal angles ; the base ...
Join BC , CK , and in the circumferences BC , CK take any points X , O , and join
BX , XC , CO , OK . then because in the triangles GBC , GCK the iwo sides BG ,
GC are equal to the two CG , GK , and that they contain equal angles ; the base ...
Side 229
From this it is manifest , that if four straight lines be continual proportionals , as
the first is to the fourth , fo is the solid parallelepiped described from the first to the
similar solid similarly described from the second ; because the first straight line ...
From this it is manifest , that if four straight lines be continual proportionals , as
the first is to the fourth , fo is the solid parallelepiped described from the first to the
similar solid similarly described from the second ; because the first straight line ...
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The Elements of Euclid, Viz: The Errors, by which Theon, Or Others, Have ... Robert Simson Uten tilgangsbegrensning - 1775 |
The Elements of Euclid: The Errors, by which Theon, Or Others, Have Long Ago ... Robert Simson Uten tilgangsbegrensning - 1762 |
The Elements of Euclid: The Errors by which Theon, Or Others, Have Long ... Robert Simson Uten tilgangsbegrensning - 1827 |
Vanlige uttrykk og setninger
added alſo altitude angle ABC angle BAC baſe becauſe Book caſe circle circle ABCD circumference common cone cylinder Definition demonſtrated deſcribed diameter divided double draw drawn equal equal angles equiangular equimultiples exceſs fame fides figure firſt folid angle fore four fourth given angle given in poſition given magnitude given ratio given ſtraight line greater half join leſs likewiſe magnitude manner meet multiple muſt oppoſite parallel parallelogram perpendicular plane produced PROP proportionals Propoſition pyramid radius reaſon rectangle rectangle contained rectilineal remaining right angles ſame ſecond ſegment ſhall ſides ſimilar ſolid ſphere ſquare ſquare of AC taken THEOR theſe third thro triangle ABC wherefore whole
Populære avsnitt
Side 156 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Side 3 - A circle is a plane figure contained by one line, which is called the circumference, and is such that all straight lines drawn from a certain point within the figure to the circumference, are equal to one another.
Side 323 - Equiangular parallelograms have to one another the ratio which is compounded of the ratios of their sides.
Side 92 - If from a point without a circle there be drawn two straight lines, one of which cuts the circle, and the other meets it ; if the rectangle contained by the whole line which cuts the circle, and the part of it without the circle, be equal to the square- of the line which meets it, the line which meets shall touch the circle.
Side 80 - EA : and because AD is equal to DC, and DE common to the triangles ADE, CDE, the two sides AD, DE are equal to the two CD, DE, each to each ; and the angle ADE is equal to the angle CDE, for each of them is a right angle ; therefore the base AE is equal (4.
Side 52 - If a straight line be bisected, and produced to any point, the square of the whole line thus produced, and the square of the part of it produced, are together double of the square of half the line bisected, and of the square of the line made up of the half and the part produced.
Side 36 - To a given straight line to apply a parallelogram, which shall be equal to a given triangle, and have one of its angles equal to a given rectilineal angle.
Side 2 - When a straight line standing on another straight line makes the adjacent angles equal to one another, each of the angles is called a right angle; and the straight line which stands on the other is called a perpendicular to it.
Side 54 - AB be the given straight line ; it is required to divide it into two parts, so that the rectangle contained by the whole, and one of the parts, shall be equal to the square of the other part.
Side 74 - The straight line drawn at right angles to the diameter of a circle, from the extremity of it, falls without the circle...