## The Elements of Euclid: The Errors, by which Theon, Or Others, Have Long Ago Vitiated These Books, are Corrected and Some of Euclid's Demonstrations are Restored. Also, The Book of Euclid's Data, in Like Manner Corrected. viz. The first six books, together with the eleventh and twelfth |

### Inni boken

Resultat 1-5 av 11

Side 34

Book 1. rallelogram EBCA , because the diameter AB bisects it ; and the triangle

DBC is the half of the parallelogram ... Let the

bases BC , EF , and between the fame parallels BF , AD . the

Book 1. rallelogram EBCA , because the diameter AB bisects it ; and the triangle

DBC is the half of the parallelogram ... Let the

**triangles ABC**, DEF be upon equalbases BC , EF , and between the fame parallels BF , AD . the

**triangle ABC**is ... Side 67

Take M the center of the circle

remainder GD , that is , GD is less than KD . and because MK , DK áre drawn to

the point K within the F

KD E A ...

Take M the center of the circle

**ABC**, and join ME , MF , MC , 6. 1. ... Az theremainder GD , that is , GD is less than KD . and because MK , DK áre drawn to

the point K within the F

**triangle**MLD from M , the extremities of its side MD ; MK ,KD E A ...

Side 148

Let the

altitude , viz . the perpendicular drawn from the ... BC is to the base CD , fo is the

CF.

Let the

**triangles ABC**, ACD , and the parallelograms EC , CF have the famealtitude , viz . the perpendicular drawn from the ... BC is to the base CD , fo is the

**triangle ABC**to the triangle ACD , and the parallelogram EC to the parallelogramCF.

Side 167

Which was to be done , PROP . XIX . THEOR , SIM IMILAR

another in the du . plicate ratio of their homologous fides . Let

similar

DE ...

Which was to be done , PROP . XIX . THEOR , SIM IMILAR

**triangles**are to oneanother in the du . plicate ratio of their homologous fides . Let

**ABC**, DEF besimilar

**triangles**having the angle B equal to the angle E , and let AB be to BC , asDE ...

Side 184

... and the

is equal to the circumference CK , the remaining part of the whole circumference

of the circle

... and the

**triangle**GBC to the**triangle**GCK . and because the circumference BCis equal to the circumference CK , the remaining part of the whole circumference

of the circle

**ABC**, is equal to the remaining part of the whole circumference of ...### Hva folk mener - Skriv en omtale

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### Andre utgaver - Vis alle

The Elements of Euclid, Viz: The Errors, by which Theon, Or Others, Have ... Robert Simson Uten tilgangsbegrensning - 1775 |

The Elements of Euclid: The Errors, by which Theon, Or Others, Have Long Ago ... Robert Simson Uten tilgangsbegrensning - 1762 |

The Elements of Euclid: The Errors by which Theon, Or Others, Have Long ... Robert Simson Uten tilgangsbegrensning - 1827 |

### Vanlige uttrykk og setninger

added alſo altitude angle ABC angle BAC baſe becauſe Book caſe circle circle ABCD circumference common cone cylinder Definition demonſtrated deſcribed diameter divided double draw drawn equal equal angles equiangular equimultiples exceſs fame fides figure firſt folid angle fore four fourth given angle given in poſition given magnitude given ratio given ſtraight line greater half join leſs likewiſe magnitude manner meet multiple muſt oppoſite parallel parallelogram perpendicular plane produced PROP proportionals Propoſition pyramid radius reaſon rectangle rectangle contained rectilineal remaining right angles ſame ſecond ſegment ſhall ſides ſimilar ſolid ſphere ſquare ſquare of AC taken THEOR theſe third thro triangle ABC wherefore whole

### Populære avsnitt

Side 156 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.

Side 3 - A circle is a plane figure contained by one line, which is called the circumference, and is such that all straight lines drawn from a certain point within the figure to the circumference, are equal to one another.

Side 323 - Equiangular parallelograms have to one another the ratio which is compounded of the ratios of their sides.

Side 92 - If from a point without a circle there be drawn two straight lines, one of which cuts the circle, and the other meets it ; if the rectangle contained by the whole line which cuts the circle, and the part of it without the circle, be equal to the square- of the line which meets it, the line which meets shall touch the circle.

Side 80 - EA : and because AD is equal to DC, and DE common to the triangles ADE, CDE, the two sides AD, DE are equal to the two CD, DE, each to each ; and the angle ADE is equal to the angle CDE, for each of them is a right angle ; therefore the base AE is equal (4.

Side 52 - If a straight line be bisected, and produced to any point, the square of the whole line thus produced, and the square of the part of it produced, are together double of the square of half the line bisected, and of the square of the line made up of the half and the part produced.

Side 36 - To a given straight line to apply a parallelogram, which shall be equal to a given triangle, and have one of its angles equal to a given rectilineal angle.

Side 2 - When a straight line standing on another straight line makes the adjacent angles equal to one another, each of the angles is called a right angle; and the straight line which stands on the other is called a perpendicular to it.

Side 54 - AB be the given straight line ; it is required to divide it into two parts, so that the rectangle contained by the whole, and one of the parts, shall be equal to the square of the other part.

Side 74 - The straight line drawn at right angles to the diameter of a circle, from the extremity of it, falls without the circle...