The Elements of Euclid: The Errors, by which Theon, Or Others, Have Long Ago Vitiated These Books, are Corrected and Some of Euclid's Demonstrations are Restored. Also, The Book of Euclid's Data, in Like Manner Corrected. viz. The first six books, together with the eleventh and twelfth |
Inni boken
Side 67
20. fi than ED , therefore also AD is greater than ED . again , because ME is
equal to MF , and MD common to the triangles EMD , FMD ; EM , MD are equal to
FM , D MD ; but the angle EMD is greater than the angle FMD , therefore the base
...
20. fi than ED , therefore also AD is greater than ED . again , because ME is
equal to MF , and MD common to the triangles EMD , FMD ; EM , MD are equal to
FM , D MD ; but the angle EMD is greater than the angle FMD , therefore the base
...
Side 101
... AC are equal to the two BA , AC ; and the base DC is equal to the base BC ;
wherefore the angle DAC is equal a to the angle BAC , and the angle DAB is
bisected E by the straight line AC . in the same manner it may be demonstrated
that the ...
... AC are equal to the two BA , AC ; and the base DC is equal to the base BC ;
wherefore the angle DAC is equal a to the angle BAC , and the angle DAB is
bisected E by the straight line AC . in the same manner it may be demonstrated
that the ...
Side 103
... of the angles at the base double of the third angle . Which was to be done . To
PRO P. XI . PROB . " O inscribe an equilateral and cquiangular pentagon in a
given circle . Let ABCDE be the given circle ; it is required to inscribe an
equilateral ...
... of the angles at the base double of the third angle . Which was to be done . To
PRO P. XI . PROB . " O inscribe an equilateral and cquiangular pentagon in a
given circle . Let ABCDE be the given circle ; it is required to inscribe an
equilateral ...
Side 148
Produce BD both ways to the points H , L , and take any number of straight lines
BG , GH , each equal to the base BC ; and DK , KL , any number of them , cach
equal to the base CD ; and join AG , AH , AK , AL . then because CB , BG , GH are
...
Produce BD both ways to the points H , L , and take any number of straight lines
BG , GH , each equal to the base BC ; and DK , KL , any number of them , cach
equal to the base CD ; and join AG , AH , AK , AL . then because CB , BG , GH are
...
Side 184
... GK , and that they contain equal angles ; the base BC is equal o to the base CK
, and the triangle GBC to the triangle GCK . and because the circumference BC is
equal to the circumference CK , the remaining part of the whole circumference ...
... GK , and that they contain equal angles ; the base BC is equal o to the base CK
, and the triangle GBC to the triangle GCK . and because the circumference BC is
equal to the circumference CK , the remaining part of the whole circumference ...
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The Elements of Euclid, Viz: The Errors, by which Theon, Or Others, Have ... Robert Simson Uten tilgangsbegrensning - 1775 |
The Elements of Euclid: The Errors, by which Theon, Or Others, Have Long Ago ... Robert Simson Uten tilgangsbegrensning - 1762 |
The Elements of Euclid: The Errors by which Theon, Or Others, Have Long ... Robert Simson Uten tilgangsbegrensning - 1827 |
Vanlige uttrykk og setninger
added alſo altitude angle ABC angle BAC baſe becauſe Book caſe circle circle ABCD circumference common cone cylinder Definition demonſtrated deſcribed diameter divided double draw drawn equal equal angles equiangular equimultiples exceſs fame fides figure firſt folid angle fore four fourth given angle given in poſition given magnitude given ratio given ſtraight line greater half join leſs likewiſe magnitude manner meet multiple muſt oppoſite parallel parallelogram perpendicular plane produced PROP proportionals Propoſition pyramid radius reaſon rectangle rectangle contained rectilineal remaining right angles ſame ſecond ſegment ſhall ſides ſimilar ſolid ſphere ſquare ſquare of AC taken THEOR theſe third thro triangle ABC wherefore whole
Populære avsnitt
Side 156 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Side 3 - A circle is a plane figure contained by one line, which is called the circumference, and is such that all straight lines drawn from a certain point within the figure to the circumference, are equal to one another.
Side 323 - Equiangular parallelograms have to one another the ratio which is compounded of the ratios of their sides.
Side 92 - If from a point without a circle there be drawn two straight lines, one of which cuts the circle, and the other meets it ; if the rectangle contained by the whole line which cuts the circle, and the part of it without the circle, be equal to the square- of the line which meets it, the line which meets shall touch the circle.
Side 80 - EA : and because AD is equal to DC, and DE common to the triangles ADE, CDE, the two sides AD, DE are equal to the two CD, DE, each to each ; and the angle ADE is equal to the angle CDE, for each of them is a right angle ; therefore the base AE is equal (4.
Side 52 - If a straight line be bisected, and produced to any point, the square of the whole line thus produced, and the square of the part of it produced, are together double of the square of half the line bisected, and of the square of the line made up of the half and the part produced.
Side 36 - To a given straight line to apply a parallelogram, which shall be equal to a given triangle, and have one of its angles equal to a given rectilineal angle.
Side 2 - When a straight line standing on another straight line makes the adjacent angles equal to one another, each of the angles is called a right angle; and the straight line which stands on the other is called a perpendicular to it.
Side 54 - AB be the given straight line ; it is required to divide it into two parts, so that the rectangle contained by the whole, and one of the parts, shall be equal to the square of the other part.
Side 74 - The straight line drawn at right angles to the diameter of a circle, from the extremity of it, falls without the circle...