Elementary Algebra: For the Use of SchoolsSanborn & Carter, 1851 - 236 sider |
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A's share a²b a²b³ a³b a³b² added ALGEBRAIC QUANTITIES arithmetical arithmetical progression arithms binomial bought bushels called cents coefficient compound interest contain denominator Divide the number dividend divisor dollars equa equal evident exponent Extract the square extracting the root factors feet find a number find the square Find the values following rule formula fraction gallons gentleman given number gives greater incomplete equations last term learner less logarithm manner miles monomials multiplied negative quantity number of terms number of yards obtain perfect square persons piece polynomials positive progression by difference progression by quotient proportion proposed ratio received Reduce remainder result second degree second term sheep shillings solution square root subtracted third tion traveled twice unknown quantity value of x whence
Populære avsnitt
Side 190 - A labourer dug two trenches, one of which was 6 yards longer than the other, for 17/. 16s., and the digging of each of them cost as many shillings per yard as there were yards in its length. What was the length of each ? Ans. 10, and 16 yards.
Side 163 - Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.
Side 121 - In a series of equal ratios, the sum of the antecedents is to the sum of the consequents as any antecedent is to its consequent.
Side 95 - What fraction is that, to the numerator of which if 1 be added, the value...
Side 141 - Multiply £ the sum of the extremes by the number of terms, and the product will be the answer 10.
Side 63 - Divide the first term of the dividend by the first term of the divisor, and write the result as the first term of the quotient. Multiply the whole divisor by the first term of the quotient, and subtract the product from the dividend.
Side 59 - Divide the coefficient of the dividend by the coefficient of the divisor.
Side 181 - Divide the number 14 into two such parts, that the quotient of the greater divided by the less, shall be to the quotient of the less divided by the greater as 16 to 9.
Side 15 - It is required to divide the number 99 into five such parts, that the first may exceed the second by 3, be less than the third by 10, greater than the fourth by 9, and less than the fifth by 16. Let x= the first part.
Side 194 - This result indicates, that there is some absurdity in the conditions of the question proposed, since in order to obtain the value of x, we must extract the root of a negative quantity, which is impossible. In order to see in what this absurdity consists, let us examine into what two parts a given number should be divided, in order that the product of these parts may be the greatest possible. Let us represent the given number by p, the product of the two parts by q, and the difference of the two...