## Elements of geometry, based on Euclid, books i-iii |

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Resultat 1-5 av 19

Side 9

Things which are

are halves of the same are equal to one another . 8 . Magnitudes which coincide

with one another , that is , which exactly fill the same space , are equal to one ...

Things which are

**double**of the same are equal to one another . 7 . Things whichare halves of the same are equal to one another . 8 . Magnitudes which coincide

with one another , that is , which exactly fill the same space , are equal to one ...

Side 41

If the sides AD , DF of the A parallelograms ABCD , DBCF , opposite to the base

BC , be terminated in the same point D , it is plain that each of the parallelograms

is

If the sides AD , DF of the A parallelograms ABCD , DBCF , opposite to the base

BC , be terminated in the same point D , it is plain that each of the parallelograms

is

**double**of the triangle DBC ( I . 34 ) , and that they are therefore equal to one ... Side 45

A DEF = A GEF , an с Е Proposition 41 . — Theorem . If a parallelogram and a

triangle be upon the same base , and between the same parallels , the

parallelogram shall be

the triangle ...

A DEF = A GEF , an с Е Proposition 41 . — Theorem . If a parallelogram and a

triangle be upon the same base , and between the same parallels , the

parallelogram shall be

**double**of the triangle . Let the parallelogram ABCD , andthe triangle ...

Side 46

Therefore the parallelogram ABCD is also

Therefore , if a parallelogram , & c . Q . E . D . AY Make BE = EC Proposition 42 . -

Problem . To describe a parallelogram that shall be equal to a given triangle ...

Therefore the parallelogram ABCD is also

**double**of the triangle EBC ( Ax . 1 ) .Therefore , if a parallelogram , & c . Q . E . D . AY Make BE = EC Proposition 42 . -

Problem . To describe a parallelogram that shall be equal to a given triangle ...

Side 52

Now the parallelogram BL is

same base BD , and between the same ... But the

Ax . 6 ) , therefore the GB , and parallelogram BL is equal to the square GB .

Now the parallelogram BL is

**double**of the triangle ABD , because they are on thesame base BD , and between the same ... But the

**doubles**of equals are equal (Ax . 6 ) , therefore the GB , and parallelogram BL is equal to the square GB .

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Elements of Geometry, Based on Euclid, Bøker 1-3 Edward Atkins Ingen forhåndsvisning tilgjengelig - 2016 |

### Vanlige uttrykk og setninger

ABCD angle ABC angle BAC angle BCD angle equal base BC BC is equal bisect centre chord circle ABC circumference coincide common Const CONSTRUCTION cqual describe diagonal diameter difference divided double draw drawn equal to CD equal to twice exterior angle extremities fall figure four given point given rectilineal given straight line gnomon greater impossible join length less Let ABC Let the straight manner meet opposite angles parallel parallelogram pass perpendicular possible produced PROOF PROOF.—Because Proposition proved rectangle contained right angles segment semicircle shown side BC sides square on AC Take taken third touches the circle triangle ABC twice the rectangle unequal whole

### Populære avsnitt

Side 35 - IF a side of any triangle be produced, the exterior angle is equal to the two interior and opposite angles; and the three interior angles of every triangle are equal to two right angles.

Side 13 - THE angles at the base of an isosceles triangle are equal to one another : and, if the equal sides be produced, the angles upon the other side of the base shall be equal. Let ABC be an isosceles triangle, of which the side AB is equal to AC, and let the straight lines AB, AC be produced to D and E.

Side 7 - A diameter of a circle is a straight line drawn through the centre, and terminated both ways by the circumference.

Side 17 - If two triangles have two sides of the one equal to two sides of the...

Side 51 - If the square described upon one of the sides of a triangle, be equal to the squares described upon the other two sides of it ; the angle contained by these two sides is a right angle.

Side 9 - If a straight line meet two straight lines, so as to make the two interior angles on the same side of it taken together less than two right angles...

Side 69 - To divide a given straight line into two parts, so that the rectangle contained by the whole, and one of the parts, may be equal to the square of the other part.

Side 9 - Things which are double of the same, are equal to one another. 7. Things which are halves of the same, are equal to one another.

Side 32 - Wherefore, if a straight line, &c. QED PROPOSITION XXVIII. THEOREM. If a straight line falling upon two other straight lines, make the exterior angle equal to the interior and opposite upon the same side of the line ; or make the interior angles upon the same side together equal to two right angles ; the two straight lines shall be parallel to one another.

Side 67 - If a straight line be bisected, and produced to any point; the rectangle contained by the whole line thus produced, and the part of it produced, together with the square of half the line bisected, is equal to the square of the straight line, which is made up of the half and the part produced.