Elements of Plane Geometry: For the Use of SchoolsLewis & Sampson, 1844 - 96 sider |
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Resultat 1-5 av 73
Side 12
... PROP . II . THEOREM . If two straight lines meet , and , at the point of their meeting , a third be drawn so as to make with them ad- jacent angles , which , taken together , are equal to two right angles , the two first lines will form ...
... PROP . II . THEOREM . If two straight lines meet , and , at the point of their meeting , a third be drawn so as to make with them ad- jacent angles , which , taken together , are equal to two right angles , the two first lines will form ...
Side 13
... PROP . III . THEOREM . If two straight lines intersect each other , the opposite angles , formed at their intersection , will be equal . If the lines AB , CD , in- tersect at E , we have to prove that the opposite an- gles CEA , BED , are ...
... PROP . III . THEOREM . If two straight lines intersect each other , the opposite angles , formed at their intersection , will be equal . If the lines AB , CD , in- tersect at E , we have to prove that the opposite an- gles CEA , BED , are ...
Side 14
... equal to the sides DF , DE , and the included angle at D ; then we have to prove that the two triangles are equal ... PROP . V. THEOREM . If two angles and an included side in one triangle be equal respectively to two angles and an ...
... equal to the sides DF , DE , and the included angle at D ; then we have to prove that the two triangles are equal ... PROP . V. THEOREM . If two angles and an included side in one triangle be equal respectively to two angles and an ...
Side 15
... equal to AC , EF equal to BC , and the angle at F equal to the angle at C. PROP . VI . THEOREM . In an isosceles triangle , the angles opposite the equal sides are equal . Let AB , BC , be the equal sides ; then we have to prove that the ...
... equal to AC , EF equal to BC , and the angle at F equal to the angle at C. PROP . VI . THEOREM . In an isosceles triangle , the angles opposite the equal sides are equal . Let AB , BC , be the equal sides ; then we have to prove that the ...
Side 16
... Prop . VI . ) If two angles of a triangle are equal , the sides oppo- site them are also equal , and the triangle is isosceles . In the triangle ABC , let the angles ABC , BAC , be equal , then we have to prove that the sides AC , BC ...
... Prop . VI . ) If two angles of a triangle are equal , the sides oppo- site them are also equal , and the triangle is isosceles . In the triangle ABC , let the angles ABC , BAC , be equal , then we have to prove that the sides AC , BC ...
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Elements of Plane Geometry: For the Use of Schools Nicholas Tillinghast Uten tilgangsbegrensning - 1844 |
Elements of Plane Geometry: For the Use of Schools Nicholas Tillinghast Uten tilgangsbegrensning - 1844 |
Elements of Plane Geometry: For the Use of Schools - Primary Source Edition Nicholas Tillinghast Ingen forhåndsvisning tilgjengelig - 2013 |
Vanlige uttrykk og setninger
ABCD adjacent angles allel alternate angles altitude angle ABC angles ABD angles is equal antecedent and consequent B. I. Ax base centre circle whose radius circumference circumscribed circumscribed circle Converse of Prop describe an arc diagonal diameter divide draw the line equal angles equal B. I. Prop equal chords equal Prop equal respectively equiangular equivalent feet given angle given line given point given side half hence the triangles hypotenuse included angle inscribed angle Let the triangles line drawn linear units longer than AC multiplied number of sides oblique lines parallel to CD parallelogram perimeter perpendicular PROBLEM prove radii rectangle regular polygons respectively equal right angles Prop right-angled triangle Scholium sides AC similar subtended tangent THEOREM three sides triangles ABC triangles are equal vertex
Populære avsnitt
Side 31 - A circle is a plane figure bounded by a curved line, every point of which is equally distant from a point within called the center.
Side 63 - The square described on the hypothenuse of a right-angled triangle is equivalent to the sum of the squares described on the other two sides.
Side 70 - The areas of two triangles which have an angle of the one equal to an angle of the other are to each other as the products of the sides including the equal angles. A D A' Hyp. In triangles ABC and A'B'C', To prove AABC A A'B'C' A'B' x A'C ' Proof. Draw the altitudes BD and B'D'.
Side 53 - In any proportion, the product of the means is equal to the product of the extremes.
Side 87 - The perimeters of two regular polygons of the same number of sides, are to each other as their homologous sides, and their areas are to each other as the squares of those sides (Prop.
Side 54 - In a series of equal ratios, any antecedent is to its consequent, as the sum of all the antecedents is to the sum of all the consequents. Let a: 6 = c: d = e :/. Then, by Art.
Side 81 - All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides.
Side 59 - The area of a parallelogram is equal to the product of its base and its height: A = bx h.
Side 61 - From this proposition it is evident, that the square described on the difference of two lines is equivalent to the sum of the squares described on the lines respectively, minus twice the rectangle contained by the lines.
Side 82 - The side of a regular hexagon inscribed in a circle is equal to the radius of the circle.