The first three books of Euclid's Elements of geometry, with theorems and problems, by T. Tate |
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Resultat 1-5 av 34
Side 10
In BD take any point F , and from a E , the greater , cut off ag equal ( 1. 3. ) to AF , the less , and join FC , GB . Because AF is equal to AG , and ab to AC ( Hyp . ) , the two sides F A , AC are equal to the two GA , A B , each to ...
In BD take any point F , and from a E , the greater , cut off ag equal ( 1. 3. ) to AF , the less , and join FC , GB . Because AF is equal to AG , and ab to AC ( Hyp . ) , the two sides F A , AC are equal to the two GA , A B , each to ...
Side 14
Q. E. D. PROP . IX . PROB . А To bisect a given rectilineal angle , that is , to divide it into two equal angles . Let B A C be the given rectilineal angle , it is required to bisect it . Take any point d in A B , and from ac cut ( 1.
Q. E. D. PROP . IX . PROB . А To bisect a given rectilineal angle , that is , to divide it into two equal angles . Let B A C be the given rectilineal angle , it is required to bisect it . Take any point d in A B , and from ac cut ( 1.
Side 15
Take any point D in Ad , and ( 1. 3. ) make ce equal to cd , and upon de describe ( 1. 1. ) the equilateral triangle DFE , and join FC ; the straight line fc drawn from the given point c is at right angles to the given straight line AB ...
Take any point D in Ad , and ( 1. 3. ) make ce equal to cd , and upon de describe ( 1. 1. ) the equilateral triangle DFE , and join FC ; the straight line fc drawn from the given point c is at right angles to the given straight line AB ...
Side 17
Take any point d upon the other side of AB , from the cenII tre c , at the distance cd , describe ( Post . 3. ) the circle EGF meeting AB in F , G ; and bisect ( 1. 10. ) FG in H , and join CF , CH , CG ; the straight line ch , drawn ...
Take any point d upon the other side of AB , from the cenII tre c , at the distance cd , describe ( Post . 3. ) the circle EGF meeting AB in F , G ; and bisect ( 1. 10. ) FG in H , and join CF , CH , CG ; the straight line ch , drawn ...
Side 19
therefore the angles CBA , A BE are equal to the angles CBA , A B D. Take away the common angle A B C , the remaining angle A B E is equal ( Ax . 3. ) to the remaining angle A B D , the less to the greater , which is impossible ...
therefore the angles CBA , A BE are equal to the angles CBA , A B D. Take away the common angle A B C , the remaining angle A B E is equal ( Ax . 3. ) to the remaining angle A B D , the less to the greater , which is impossible ...
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Vanlige uttrykk og setninger
A B C ABCD adjacent angle ABC angle ACB angle BAC angle equal base BC BC is equal bisect centre circle ABC circumference coincide common construct demonstrated describe diameter divided double draw equal angles equal to FB equilateral exterior angle extremity figure fore four given point given straight line greater impossible interior join less Let ABC likewise lines AC manner meet opposite angles opposite sides parallel parallelogram pass perpendicular PROB produced Q. E. D. PROP rectangle A B rectangle contained remaining remaining angle right angles segment semicircle shown sides squares of AC straight line A B Take taken THEOR third touch touches the circle triangle ABC twice the rectangle Wherefore whole
Bibliografisk informasjon
| Tittel | The first three books of Euclid's Elements of geometry, with theorems and problems, by T. Tate Gleig's sch. series |
| Forfatter | Euclides |
| Redaktør | Thomas Tate |
| distribuert | 1851 |
| Original fra | Oxford University |
| Digitalisert | 30. jan 2009 |
| Lengde | 139 sider |
| Eksporter sitat | BiBTeX EndNote RefMan |