The first three books of Euclid's Elements of geometry, with theorems and problems, by T. Tate1851 - 139 sider |
Inni boken
Resultat 1-5 av 71
Side 6
... wherefore CA , AB , BC are equal to one another ; and the triangle ABC is therefore equilateral , and it is described upon the given straight line AB . Which was required to be done . CB ; PROP . II . PROB . From a given point 6 ...
... wherefore CA , AB , BC are equal to one another ; and the triangle ABC is therefore equilateral , and it is described upon the given straight line AB . Which was required to be done . CB ; PROP . II . PROB . From a given point 6 ...
Side 7
... wherefore AL and BC are each of them equal to BG ; and things that are equal to the same are equal to one another ; therefore the straight line A L is equal to B C. Wherefore from the given point A a straight line AL has been drawn ...
... wherefore AL and BC are each of them equal to BG ; and things that are equal to the same are equal to one another ; therefore the straight line A L is equal to B C. Wherefore from the given point A a straight line AL has been drawn ...
Side 8
... wherefore the straight line AE is equal to c ( Ax . 1. ) , and from AB , the greater of two straight lines , a part AE has been cut off equal to c the less . Which was to be done . PROP . IV . THEOREM . If two triangles have two sides ...
... wherefore the straight line AE is equal to c ( Ax . 1. ) , and from AB , the greater of two straight lines , a part AE has been cut off equal to c the less . Which was to be done . PROP . IV . THEOREM . If two triangles have two sides ...
Side 9
... wherefore also the point c shall coincide with the point F , because the straight line AC is equal to DF ( Hyp . ) . But the point в coincides with the point E ; wherefore the base BC shall co- incide with the base EF , because the ...
... wherefore also the point c shall coincide with the point F , because the straight line AC is equal to DF ( Hyp . ) . But the point в coincides with the point E ; wherefore the base BC shall co- incide with the base EF , because the ...
Side 11
... is not unequal to AC , that is , it is equal to it . Wherefore , if two angles , & c . Q. E. D. COR . Hence every equiangular triangle is also equilateral . PROP . VII . THEOR . Upon the same base BOOK I. PROP . VI . 11.
... is not unequal to AC , that is , it is equal to it . Wherefore , if two angles , & c . Q. E. D. COR . Hence every equiangular triangle is also equilateral . PROP . VII . THEOR . Upon the same base BOOK I. PROP . VI . 11.
Andre utgaver - Vis alle
The first three books of Euclid's Elements of geometry, with theorems and ... Euclid,Thomas Tate Uten tilgangsbegrensning - 1849 |
The First Three Books of Euclid's Elements of Geometry from the Text of Dr ... Euclid,Thomas Tate Ingen forhåndsvisning tilgjengelig - 2014 |
The First Three Books of Euclid's Elements of Geometry from the Text of Dr ... Euclid,Thomas Tate Ingen forhåndsvisning tilgjengelig - 2014 |
Vanlige uttrykk og setninger
A B C ABCD adjacent angles angle ABC angle ACB angle BAC angle equal angles BGH base BC BC is equal bisect centre circle ABC circumference diameter divided double draw a straight equal angles equal circles equal straight lines equal to FB exterior angle given point given rectilineal angle given straight line gnomon greater half a right hypotenuse interior and opposite isosceles triangle less Let ABC Let the straight line be drawn opposite angles parallel parallelogram perpendicular PROB produced Q. E. D. PROP rectangle AE rectangle contained rectilineal figure remaining angle right angles segment semicircle side BC square of AC straight line AB straight line AC straight line drawn THEOR touches the circle trapezium triangle ABC twice the rectangle vertex vertical angle