The first three books of Euclid's Elements of geometry, with theorems and problems, by T. Tate1851 - 139 sider |
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Side 8
... angle BAC equal to the angle EDF , the base BC shall be equal to the base EF ; B and the triangle ABC to the A.A CE T triangle DEF ; and the other angles , to which the equal sides are opposite , shall be equal each to each , viz . the ...
... angle BAC equal to the angle EDF , the base BC shall be equal to the base EF ; B and the triangle ABC to the A.A CE T triangle DEF ; and the other angles , to which the equal sides are opposite , shall be equal each to each , viz . the ...
Side 9
... angle BAC is equal to the angle EDF ( Hyp . ) ; wherefore also the point c shall coincide with the point F , because the straight line AC is equal to DF ( Hyp . ) . But the point в coincides with the point E ; wherefore the base BC ...
... angle BAC is equal to the angle EDF ( Hyp . ) ; wherefore also the point c shall coincide with the point F , because the straight line AC is equal to DF ( Hyp . ) . But the point в coincides with the point E ; wherefore the base BC ...
Side 13
Euclides Thomas Tate. then is the angle B D C greater than the angle BCD . Again , because C B is equal to D B , the ... BAC is equal to the angle E DF . B D G CE For if the triangle ABC be applied to DEF , so that the point в be on ...
Euclides Thomas Tate. then is the angle B D C greater than the angle BCD . Again , because C B is equal to D B , the ... BAC is equal to the angle E DF . B D G CE For if the triangle ABC be applied to DEF , so that the point в be on ...
Side 14
... angle BAC coincides with the angle E D F , and is equal ( Ax . 8. ) to it . There- fore if two triangles , & c . Q. E. D. PROP . IX . PROB . To bisect a given rectilineal angle , that is , to divide it into two equal angles . Let BAC be ...
... angle BAC coincides with the angle E D F , and is equal ( Ax . 8. ) to it . There- fore if two triangles , & c . Q. E. D. PROP . IX . PROB . To bisect a given rectilineal angle , that is , to divide it into two equal angles . Let BAC be ...
Side 21
... angle ACD , is greater than the Therefore , if one side , & c . Q. E. D. angle ABC . PROP . XVII . THEOR . ( Any two ... BAC , AC B , as also CAB , ABC , are less than two right , angles . Therefore any two angles , & c . Q. E. D. ...
... angle ACD , is greater than the Therefore , if one side , & c . Q. E. D. angle ABC . PROP . XVII . THEOR . ( Any two ... BAC , AC B , as also CAB , ABC , are less than two right , angles . Therefore any two angles , & c . Q. E. D. ...
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Vanlige uttrykk og setninger
A B C ABCD adjacent angles angle ABC angle ACB angle BAC angle equal angles BGH base BC BC is equal bisect centre circle ABC circumference diameter divided double draw a straight equal angles equal circles equal straight lines equal to FB exterior angle given point given rectilineal angle given straight line gnomon greater half a right hypotenuse interior and opposite isosceles triangle less Let ABC Let the straight line be drawn opposite angles parallel parallelogram perpendicular PROB produced Q. E. D. PROP rectangle AE rectangle contained rectilineal figure remaining angle right angles segment semicircle side BC square of AC straight line AB straight line AC straight line drawn THEOR touches the circle trapezium triangle ABC twice the rectangle vertex vertical angle