The first three books of Euclid's Elements of geometry, with theorems and problems, by T. Tate1851 - 139 sider |
Inni boken
Resultat 1-5 av 36
Side 14
... bisect a given rectilineal angle , that is , to divide it into two equal angles . Let BAC be the given rectilineal angle , it is re- quired to bisect it . Take any point D in A B , and from AC cut ( 1. 3. ) off A E equal to A D ; join ...
... bisect a given rectilineal angle , that is , to divide it into two equal angles . Let BAC be the given rectilineal angle , it is re- quired to bisect it . Take any point D in A B , and from AC cut ( 1. 3. ) off A E equal to A D ; join ...
Side 15
... bisect ( 1. 9. ) the angle A C B by the straight AB is cut into two equal parts in the line C D. point D. C Because AC is equal to C B , and CD common to the two triangles ACD , BCD ; the two sides A C , CD are equal to BC , CD , each ...
... bisect ( 1. 9. ) the angle A C B by the straight AB is cut into two equal parts in the line C D. point D. C Because AC is equal to C B , and CD common to the two triangles ACD , BCD ; the two sides A C , CD are equal to BC , CD , each ...
Side 17
... bisect ( 1. 10. ) FG in H , and join CF , CH , CG ; the straight line cH , drawn from the given point c , is perpendicular to the given straight line AB . Because FH is equal to HG , and HC common to the two triangles FHC , GHC , the ...
... bisect ( 1. 10. ) FG in H , and join CF , CH , CG ; the straight line cH , drawn from the given point c , is perpendicular to the given straight line AB . Because FH is equal to HG , and HC common to the two triangles FHC , GHC , the ...
Side 20
... Bisect ( 1. 10. ) AC in E , join BE and produce it to F , and make EF equal to BE ; B join also FC , and produce AC to G. G Because A E is equal to EC and BE to EF ; AE , E B are equal to CE , EF , each to each ; and the angle A E B is ...
... Bisect ( 1. 10. ) AC in E , join BE and produce it to F , and make EF equal to BE ; B join also FC , and produce AC to G. G Because A E is equal to EC and BE to EF ; AE , E B are equal to CE , EF , each to each ; and the angle A E B is ...
Side 36
... bisects them , that is , divides them in two equal parts . N.B. - A parallelogram is a four - sided figure , of which the opposite sides are parallel ; and the diameter is the straight line joining two of its opposite angles . Let ACDB ...
... bisects them , that is , divides them in two equal parts . N.B. - A parallelogram is a four - sided figure , of which the opposite sides are parallel ; and the diameter is the straight line joining two of its opposite angles . Let ACDB ...
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Vanlige uttrykk og setninger
A B C ABCD adjacent angles angle ABC angle ACB angle BAC angle equal angles BGH base BC BC is equal bisect centre circle ABC circumference diameter divided double draw a straight equal angles equal circles equal straight lines equal to FB exterior angle given point given rectilineal angle given straight line gnomon greater half a right hypotenuse interior and opposite isosceles triangle less Let ABC Let the straight line be drawn opposite angles parallel parallelogram perpendicular PROB produced Q. E. D. PROP rectangle AE rectangle contained rectilineal figure remaining angle right angles segment semicircle side BC square of AC straight line AB straight line AC straight line drawn THEOR touches the circle trapezium triangle ABC twice the rectangle vertex vertical angle