The first three books of Euclid's Elements of geometry, with theorems and problems, by T. Tate |
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Resultat 1-5 av 36
Side 14
А To bisect a given rectilineal angle , that is , to divide it into two equal angles . Let B A C be the given rectilineal angle , it is required to bisect it . Take any point d in A B , and from ac cut ( 1. 3. ) ...
А To bisect a given rectilineal angle , that is , to divide it into two equal angles . Let B A C be the given rectilineal angle , it is required to bisect it . Take any point d in A B , and from ac cut ( 1. 3. ) ...
Side 15
To bisect a given finite straight line , that is , to divide it into two equal parts . Let A B be the given straight line ; it is required to divide it into two equal parts . Describe ( 1. 1. ) upon it an equilateral triangle A B C ...
To bisect a given finite straight line , that is , to divide it into two equal parts . Let A B be the given straight line ; it is required to divide it into two equal parts . Describe ( 1. 1. ) upon it an equilateral triangle A B C ...
Side 17
the circle EGF meeting AB in F , G ; and bisect ( 1. 10. ) FG in H , and join CF , CH , CG ; the straight line ch , drawn from the given point c , is perpendicular to the given straight line AB . Because Fh is equal to hd , and no ...
the circle EGF meeting AB in F , G ; and bisect ( 1. 10. ) FG in H , and join CF , CH , CG ; the straight line ch , drawn from the given point c , is perpendicular to the given straight line AB . Because Fh is equal to hd , and no ...
Side 20
Bisect ( 1. 10. ) AC in E , join B E and produce it to F , and make E F equal to BE ; B join also FC , and produce AC to G. Because A E is equal to EC and BE to EF ; A E , E B are equal to CE , E F , each to each ; and the angle A E B ...
Bisect ( 1. 10. ) AC in E , join B E and produce it to F , and make E F equal to BE ; B join also FC , and produce AC to G. Because A E is equal to EC and BE to EF ; A E , E B are equal to CE , E F , each to each ; and the angle A E B ...
Side 36
The opposite sides and angles of parallelograms are equal to one another , and the diameter bisects them , that is , divides them in two equal parts . N.B.— A parallelogram is a four - sided figure , of which the opposite sides are ...
The opposite sides and angles of parallelograms are equal to one another , and the diameter bisects them , that is , divides them in two equal parts . N.B.— A parallelogram is a four - sided figure , of which the opposite sides are ...
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Vanlige uttrykk og setninger
A B C ABCD adjacent angle ABC angle ACB angle BAC angle equal base BC BC is equal bisect centre circle ABC circumference coincide common construct demonstrated describe diameter divided double draw equal angles equal to FB equilateral exterior angle extremity figure fore four given point given straight line greater impossible interior join less Let ABC likewise lines AC manner meet opposite angles opposite sides parallel parallelogram pass perpendicular PROB produced Q. E. D. PROP rectangle A B rectangle contained remaining remaining angle right angles segment semicircle shown sides squares of AC straight line A B Take taken THEOR third touch touches the circle triangle ABC twice the rectangle Wherefore whole
Bibliografisk informasjon
| Tittel | The first three books of Euclid's Elements of geometry, with theorems and problems, by T. Tate Gleig's sch. series |
| Forfatter | Euclides |
| Redaktør | Thomas Tate |
| distribuert | 1851 |
| Original fra | Oxford University |
| Digitalisert | 30. jan 2009 |
| Lengde | 139 sider |
| Eksporter sitat | BiBTeX EndNote RefMan |