The first three books of Euclid's Elements of geometry, with theorems and problems, by T. Tate1851 - 139 sider |
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Resultat 1-5 av 35
Side 10
... common to the two triangles AFC , AGB ; therefore the base FC is equal ( 1. 4. ) to the base GB , and the triangle AFC to the triangle AGB ; and the remain- ing angles of the one are equal- ( 1.4 . ) to the remaining angles of the other ...
... common to the two triangles AFC , AGB ; therefore the base FC is equal ( 1. 4. ) to the base GB , and the triangle AFC to the triangle AGB ; and the remain- ing angles of the one are equal- ( 1.4 . ) to the remaining angles of the other ...
Side 11
... common to both , the two sides DB , BC are equal to the two AC , CB , each to each ; and the angle DBC is equal to the angle ACB ( Hyp . ) ; therefore the base DC is equal to the base AB , and the triangle DBC is equal to the triangle ...
... common to both , the two sides DB , BC are equal to the two AC , CB , each to each ; and the angle DBC is equal to the angle ACB ( Hyp . ) ; therefore the base DC is equal to the base AB , and the triangle DBC is equal to the triangle ...
Side 14
... common to the two triangles DAF , EAF ; the two sides DA , A F , are equal to the two sides E A , AF , each to each ; and the base DF is equal to the base E F ; therefore the B D A E C angle DAF is equal ( 1. 8. ) to the angle EA F ...
... common to the two triangles DAF , EAF ; the two sides DA , A F , are equal to the two sides E A , AF , each to each ; and the base DF is equal to the base E F ; therefore the B D A E C angle DAF is equal ( 1. 8. ) to the angle EA F ...
Side 15
... common to the two triangles ACD , BCD ; the two sides A C , CD are equal to BC , CD , each to each : and the angle ACD is equal to the angle BCD ( Constr . ) ; therefore the base A D is equal to the base ( 1. 4. ) D B , and the straight ...
... common to the two triangles ACD , BCD ; the two sides A C , CD are equal to BC , CD , each to each : and the angle ACD is equal to the angle BCD ( Constr . ) ; therefore the base A D is equal to the base ( 1. 4. ) D B , and the straight ...
Side 16
... common segment . E If it be possible , let the two straight lines A B C , ABD , have the segment A B common to both of them . From the point в draw BE at right angles to AB ; and because ABC is a straight line , the angle CBE is equal ...
... common segment . E If it be possible , let the two straight lines A B C , ABD , have the segment A B common to both of them . From the point в draw BE at right angles to AB ; and because ABC is a straight line , the angle CBE is equal ...
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Vanlige uttrykk og setninger
A B C ABCD adjacent angles angle ABC angle ACB angle BAC angle equal angles BGH base BC BC is equal bisect centre circle ABC circumference diameter divided double draw a straight equal angles equal circles equal straight lines equal to FB exterior angle given point given rectilineal angle given straight line gnomon greater half a right hypotenuse interior and opposite isosceles triangle less Let ABC Let the straight line be drawn opposite angles parallel parallelogram perpendicular PROB produced Q. E. D. PROP rectangle AE rectangle contained rectilineal figure remaining angle right angles segment semicircle side BC square of AC straight line AB straight line AC straight line drawn THEOR touches the circle trapezium triangle ABC twice the rectangle vertex vertical angle