The first three books of Euclid's Elements of geometry, with theorems and problems, by T. Tate1851 - 139 sider |
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Resultat 1-5 av 35
Side 10
... common to the two triangles AFC , AGB ; therefore the base FC is equal ( 1. 4. ) to the base GB , and the triangle AFC to the triangle AGB ; and the remain- ing angles of the one are equal- ( 1.4 . ) to the remaining angles of the other ...
... common to the two triangles AFC , AGB ; therefore the base FC is equal ( 1. 4. ) to the base GB , and the triangle AFC to the triangle AGB ; and the remain- ing angles of the one are equal- ( 1.4 . ) to the remaining angles of the other ...
Side 11
... common to both , the two sides DB , BC are equal to the two AC , CB , each to each ; and the angle DBC is equal to the angle ACB ( Hyp . ) ; therefore the base DC is equal to the base AB , and the triangle DBC is equal to the triangle ...
... common to both , the two sides DB , BC are equal to the two AC , CB , each to each ; and the angle DBC is equal to the angle ACB ( Hyp . ) ; therefore the base DC is equal to the base AB , and the triangle DBC is equal to the triangle ...
Side 14
... common to the two triangles DAF , EAF ; the two sides DA , A F , are equal to the two sides E A , AF , each to each ; and the base DF is equal to the base E F ; therefore the B D F Α angle DAF is equal ( 1. 8. ) to the angle E A F ...
... common to the two triangles DAF , EAF ; the two sides DA , A F , are equal to the two sides E A , AF , each to each ; and the base DF is equal to the base E F ; therefore the B D F Α angle DAF is equal ( 1. 8. ) to the angle E A F ...
Side 15
... common to the two triangles ACD , BCD ; the two sides a C , CD are equal to B C , CD , each to each : and the angle ACD is equal to the angle BCD ( Constr . ) ; therefore the base AD is equal to the base ( I. 4. ) D B , straight line AB ...
... common to the two triangles ACD , BCD ; the two sides a C , CD are equal to B C , CD , each to each : and the angle ACD is equal to the angle BCD ( Constr . ) ; therefore the base AD is equal to the base ( I. 4. ) D B , straight line AB ...
Side 16
... common segment . E If it be possible , let the two straight lines A B C , ABD , have the segment A B common to both of them . From the point в draw BE at right angles to AB ; and because ABC is a straight line , the angle CBE is equal ...
... common segment . E If it be possible , let the two straight lines A B C , ABD , have the segment A B common to both of them . From the point в draw BE at right angles to AB ; and because ABC is a straight line , the angle CBE is equal ...
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Vanlige uttrykk og setninger
A B C ABCD adjacent alternate angle ABC angle ACB angle BAC angle equal base BC BC is equal bisect centre circle ABC circumference coincide common construct demonstrated describe diameter divided double draw equal angles equilateral exterior angle extremity figure fore four given point given straight line gnomon greater impossible interior join less Let ABC Let the straight likewise manner meet opposite angles opposite sides parallel parallelogram pass perpendicular PROB produced Q. E. D. PROP rectangle contained remaining remaining angle right angles segment semicircle shown sides square of AC straight line AC Take taken THEOR third touch touches the circle triangle ABC twice the rectangle vertex Wherefore whole