The first three books of Euclid's Elements of geometry, with theorems and problems, by T. Tate |
Inni boken
Resultat 1-5 av 85
Side 10
to AF , the less , and join FC , GB . Because AF is equal to AG , and ab to AC ( Hyp . ) , the two sides F A , AC are equal to the two GA , A B , each to each ; and they contain the angle FAG common to the two A triangles AFC ...
to AF , the less , and join FC , GB . Because AF is equal to AG , and ab to AC ( Hyp . ) , the two sides F A , AC are equal to the two GA , A B , each to each ; and they contain the angle FAG common to the two A triangles AFC ...
Side 11
off DB equal to Ac , the less , and join DC ; therefore , because in the triangles DBC , ACB , DB is equal to Ac , and BC common to both , the two sides DB , BC are equal to the two AC ...
off DB equal to Ac , the less , and join DC ; therefore , because in the triangles DBC , ACB , DB is equal to Ac , and BC common to both , the two sides DB , BC are equal to the two AC ...
Side 12
... and likewise their sides CB , DB , and are terminated in B. Join CD ; then , in the case in which the vertex of each of the A B triangles is without the other triangle , because AC is equal to AD , the angle ACD is equal ( 1. 5. ) ...
... and likewise their sides CB , DB , and are terminated in B. Join CD ; then , in the case in which the vertex of each of the A B triangles is without the other triangle , because AC is equal to AD , the angle ACD is equal ( 1. 5. ) ...
Side 14
an equilateral triangle DEF ; then join A F ; the straight line AF bisects the triangle B A C. Because Ad is equal to A E , and A F is common to the two triangles DAF , EAF ; the two sides DA , A F , are equal to the two sides E A ...
an equilateral triangle DEF ; then join A F ; the straight line AF bisects the triangle B A C. Because Ad is equal to A E , and A F is common to the two triangles DAF , EAF ; the two sides DA , A F , are equal to the two sides E A ...
Side 17
FG in H , and join CF , CH , CG ; the straight line ch , drawn from the given point c , is perpendicular to the given straight line AB . Because Fh is equal to hd , and no common to the two triangles FHC , GHC , the two sides FH ...
FG in H , and join CF , CH , CG ; the straight line ch , drawn from the given point c , is perpendicular to the given straight line AB . Because Fh is equal to hd , and no common to the two triangles FHC , GHC , the two sides FH ...
Hva folk mener - Skriv en omtale
Vi har ikke funnet noen omtaler på noen av de vanlige stedene.
Andre utgaver - Vis alle
The first three books of Euclid's Elements of geometry, with theorems and ... Euclid,Thomas Tate Uten tilgangsbegrensning - 1849 |
The First Three Books of Euclid's Elements of Geometry from the Text of Dr ... Euclid,Thomas Tate Ingen forhåndsvisning tilgjengelig - 2014 |
The First Three Books of Euclid's Elements of Geometry from the Text of Dr ... Euclid,Thomas Tate Ingen forhåndsvisning tilgjengelig - 2014 |
Vanlige uttrykk og setninger
A B C ABCD adjacent angle ABC angle ACB angle BAC angle equal base BC BC is equal bisect centre circle ABC circumference coincide common construct demonstrated describe diameter divided double draw equal angles equal to FB equilateral exterior angle extremity figure fore four given point given straight line greater impossible interior join less Let ABC likewise lines AC manner meet opposite angles opposite sides parallel parallelogram pass perpendicular PROB produced Q. E. D. PROP rectangle A B rectangle contained remaining remaining angle right angles segment semicircle shown sides squares of AC straight line A B Take taken THEOR third touch touches the circle triangle ABC twice the rectangle Wherefore whole
Bibliografisk informasjon
| Tittel | The first three books of Euclid's Elements of geometry, with theorems and problems, by T. Tate Gleig's sch. series |
| Forfatter | Euclides |
| Redaktør | Thomas Tate |
| distribuert | 1851 |
| Original fra | Oxford University |
| Digitalisert | 30. jan 2009 |
| Lengde | 139 sider |
| Eksporter sitat | BiBTeX EndNote RefMan |