The first three books of Euclid's Elements of geometry, with theorems and problems, by T. Tate1851 - 139 sider |
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Resultat 1-5 av 18
Side 47
... rectangular , and it has been demonstrated that it is equilateral ; it is therefore a square ( Def . 30. ) , and it is described upon the given straight line AB . Which was to be done . COR . Hence every parallelogram that has one right ...
... rectangular , and it has been demonstrated that it is equilateral ; it is therefore a square ( Def . 30. ) , and it is described upon the given straight line AB . Which was to be done . COR . Hence every parallelogram that has one right ...
Side 51
... rectangle BH is equal to the rectangles BK , DL , EH ; and BH is contained by A , BC , for it is contained by GB ... AB be divided into any two parts in the point c ; the rectangle contained by A B , BC , together with the rectangle * AB ...
... rectangle BH is equal to the rectangles BK , DL , EH ; and BH is contained by A , BC , for it is contained by GB ... AB be divided into any two parts in the point c ; the rectangle contained by A B , BC , together with the rectangle * AB ...
Side 52
Euclides Thomas Tate. equal to AB ; therefore the rectangle contained by AB , AC together with the rectangle AB , BC , is equal to the square of AB . If therefore a straight line , Q.E.D. & c . PROP . III . THEOR . If a straight line be ...
Euclides Thomas Tate. equal to AB ; therefore the rectangle contained by AB , AC together with the rectangle AB , BC , is equal to the square of AB . If therefore a straight line , Q.E.D. & c . PROP . III . THEOR . If a straight line be ...
Side 53
... AB describe ( 1. 46. ) the square ADEB , and join BD , and through c draw ( I. 31. ) CGF parallel to AD or BE , and ... rectangle contained by AC , CB , for GC is equal to CB ; Therefore GE is also equal to the rectangle AC , CB ...
... AB describe ( 1. 46. ) the square ADEB , and join BD , and through c draw ( I. 31. ) CGF parallel to AD or BE , and ... rectangle contained by AC , CB , for GC is equal to CB ; Therefore GE is also equal to the rectangle AC , CB ...
Side 54
Euclides Thomas Tate. is the square of AB : Therefore the square of AB is equal to the squares of AC , CB and twice the rectangle AC , CB . Wherefore if a straight line , & c . Q. E. D. COR . From the demonstration , it is manifest that ...
Euclides Thomas Tate. is the square of AB : Therefore the square of AB is equal to the squares of AC , CB and twice the rectangle AC , CB . Wherefore if a straight line , & c . Q. E. D. COR . From the demonstration , it is manifest that ...
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Vanlige uttrykk og setninger
A B C ABCD adjacent alternate angle ABC angle ACB angle BAC angle equal base BC BC is equal bisect centre circle ABC circumference coincide common construct demonstrated describe diameter divided double draw equal angles equilateral exterior angle extremity figure fore four given point given straight line gnomon greater impossible interior join less Let ABC Let the straight likewise manner meet opposite angles opposite sides parallel parallelogram pass perpendicular PROB produced Q. E. D. PROP rectangle contained remaining remaining angle right angles segment semicircle shown sides square of AC straight line AC Take taken THEOR third touch touches the circle triangle ABC twice the rectangle vertex Wherefore whole