The first three books of Euclid's Elements of geometry, with theorems and problems, by T. Tate |
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Resultat 1-5 av 18
Side 47
E А B is a parallelogram : whence AB is equal ( 1. ... therefore each of the opposite angles A BE , BED is a right angle ; wherefore the figure ADEB is rectangular , and it has been demonstrated that it is equilateral ; it is therefore ...
E А B is a parallelogram : whence AB is equal ( 1. ... therefore each of the opposite angles A BE , BED is a right angle ; wherefore the figure ADEB is rectangular , and it has been demonstrated that it is equilateral ; it is therefore ...
Side 51
DK , EL , ch parallel to Bg ; then the rectangle bu is equal to the rectangles EK , DL , EH ; and Bh is contained by A , BC , for ... Let the straight line AB be divided into any two parts in the point c ; the rectangle contained by A B ...
DK , EL , ch parallel to Bg ; then the rectangle bu is equal to the rectangles EK , DL , EH ; and Bh is contained by A , BC , for ... Let the straight line AB be divided into any two parts in the point c ; the rectangle contained by A B ...
Side 52
equal to AB ; therefore the rectangle contained by A B , AC together with the rectangle A B , BC , is equal to the square of A B. If therefore a straight line , & c . Q.E.D. с B PROP . III . THEOR . If a straight line be divided into ...
equal to AB ; therefore the rectangle contained by A B , AC together with the rectangle A B , BC , is equal to the square of A B. If therefore a straight line , & c . Q.E.D. с B PROP . III . THEOR . If a straight line be divided into ...
Side 53
D F E G K of AC , BC , together with twice the rectangle contained by AC , CB . Upon A B describe ( 1. 46. ) the square ADE B , and join BD , and through c draw ( 1. 31. ) CGF parallel to AD or BE , and through a draw HK parallel to AB ...
D F E G K of AC , BC , together with twice the rectangle contained by AC , CB . Upon A B describe ( 1. 46. ) the square ADE B , and join BD , and through c draw ( 1. 31. ) CGF parallel to AD or BE , and through a draw HK parallel to AB ...
Side 54
is the square of AB : Therefore the square of AB is equal to the squares of AC , CB and twice the rectangle AC , CB . Wherefore if a straight line , & c . Q. E. D. Cor . From the demonstration , it is manifest that the parallelograms ...
is the square of AB : Therefore the square of AB is equal to the squares of AC , CB and twice the rectangle AC , CB . Wherefore if a straight line , & c . Q. E. D. Cor . From the demonstration , it is manifest that the parallelograms ...
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Vanlige uttrykk og setninger
A B C ABCD adjacent angle ABC angle ACB angle BAC angle equal base BC BC is equal bisect centre circle ABC circumference coincide common construct demonstrated describe diameter divided double draw equal angles equal to FB equilateral exterior angle extremity figure fore four given point given straight line greater impossible interior join less Let ABC likewise lines AC manner meet opposite angles opposite sides parallel parallelogram pass perpendicular PROB produced Q. E. D. PROP rectangle A B rectangle contained remaining remaining angle right angles segment semicircle shown sides squares of AC straight line A B Take taken THEOR third touch touches the circle triangle ABC twice the rectangle Wherefore whole