The first three books of Euclid's Elements of geometry, with theorems and problems, by T. Tate1851 - 139 sider |
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Resultat 1-5 av 24
Side 7
... shown that BC is equal to BG ; wherefore AL and BC are each of them equal to BG ; and things that are equal to the same are equal to one another ; therefore the straight line A L is equal to B C. Wherefore from the given point A a ...
... shown that BC is equal to BG ; wherefore AL and BC are each of them equal to BG ; and things that are equal to the same are equal to one another ; therefore the straight line A L is equal to B C. Wherefore from the given point A a ...
Side 22
... shown that it is not equal to A B ; therefore A C is greater than A B. Wherefore the angle , & c . Q. E. D. PROP . XX . THEOR . ; Any two sides of a triangle are together greater than the third side . Let ABC be a triangle ; any two ...
... shown that it is not equal to A B ; therefore A C is greater than A B. Wherefore the angle , & c . Q. E. D. PROP . XX . THEOR . ; Any two sides of a triangle are together greater than the third side . Let ABC be a triangle ; any two ...
Side 23
... shown that B A , A C are greater than B E , EC ; much more then are B A , A C greater than B D , D C. Again , because the exterior angle of a triangle is greater than the interior and opposite angle ( 1. BOOK I. PROP . XXI . 23.
... shown that B A , A C are greater than B E , EC ; much more then are B A , A C greater than B D , D C. Again , because the exterior angle of a triangle is greater than the interior and opposite angle ( 1. BOOK I. PROP . XXI . 23.
Side 27
... shown that it is not equal to it ; therefore the angle B A C is greater than the angle EDF . Wherefore if two triangles , & c . Q. E. D. PROP . XXVI . THEOR . If two triangles have two angles of one equal to two angles of the other ...
... shown that it is not equal to it ; therefore the angle B A C is greater than the angle EDF . Wherefore if two triangles , & c . Q. E. D. PROP . XXVI . THEOR . If two triangles have two angles of one equal to two angles of the other ...
Side 33
... shown that the angle AGK is equal to the angle GHF ; therefore also AGK is equal to GKD ; and they are alternate angles ; therefore AB is parallel ( 1. 27. ) to CD . Wherefore straight lines , & c . Q. E. D. PROP . XXXI . PROB . To draw ...
... shown that the angle AGK is equal to the angle GHF ; therefore also AGK is equal to GKD ; and they are alternate angles ; therefore AB is parallel ( 1. 27. ) to CD . Wherefore straight lines , & c . Q. E. D. PROP . XXXI . PROB . To draw ...
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Vanlige uttrykk og setninger
A B C ABCD adjacent angles angle ABC angle ACB angle BAC angle equal angles BGH base BC BC is equal bisect centre circle ABC circumference diameter divided double draw a straight equal angles equal circles equal straight lines equal to FB exterior angle given point given rectilineal angle given straight line gnomon greater half a right hypotenuse interior and opposite isosceles triangle less Let ABC Let the straight line be drawn opposite angles parallel parallelogram perpendicular PROB produced Q. E. D. PROP rectangle AE rectangle contained rectilineal figure remaining angle right angles segment semicircle side BC square of AC straight line AB straight line AC straight line drawn THEOR touches the circle trapezium triangle ABC twice the rectangle vertex vertical angle