The first three books of Euclid's Elements of geometry, with theorems and problems, by T. Tate1851 - 139 sider |
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Side 6
... ABC shall be an equilateral triangle . Because the point A is the centre of the circle BCD , AC is equal ( Definition 15. ) to AB ; and because the point B is the centre of the circle ACE , BC is equal to BA : But it has been proved ...
... ABC shall be an equilateral triangle . Because the point A is the centre of the circle BCD , AC is equal ( Definition 15. ) to AB ; and because the point B is the centre of the circle ACE , BC is equal to BA : But it has been proved ...
Side 8
... triangle ABC to the AA triangle DEF ; and the other angles , to which the equal sides are opposite , shall be equal each to each , viz . the angle ABC to the angle DEF , 8 EUCLID'S ELEMENTS .
... triangle ABC to the AA triangle DEF ; and the other angles , to which the equal sides are opposite , shall be equal each to each , viz . the angle ABC to the angle DEF , 8 EUCLID'S ELEMENTS .
Side 9
... triangle ABC be applied to DEF , SO that the point A may be on D , and the straight line AB upon DE ; the point в ... triangle ABC shall coincide with the whole triangle DEF , and be equal to it ; and the other angles of the one shall ...
... triangle ABC be applied to DEF , SO that the point A may be on D , and the straight line AB upon DE ; the point в ... triangle ABC shall coincide with the whole triangle DEF , and be equal to it ; and the other angles of the one shall ...
Side 10
Euclides Thomas Tate. Let ABC be an isosceles triangle , of which the side AB is equal to A C , and let the straight lines A B , AC be produced to D and E , the angle ABC shall be equal to the angle ACB , and the angle CBD to the angle ...
Euclides Thomas Tate. Let ABC be an isosceles triangle , of which the side AB is equal to A C , and let the straight lines A B , AC be produced to D and E , the angle ABC shall be equal to the angle ACB , and the angle CBD to the angle ...
Side 11
... ABC : And it has also been proved that the angle FBC is equal to the angle GCB , which are the angles upon the other side of the base . Therefore the angles at the base , & c . Q. E. D. COROLLARY . Hence every equilateral triangle ...
... ABC : And it has also been proved that the angle FBC is equal to the angle GCB , which are the angles upon the other side of the base . Therefore the angles at the base , & c . Q. E. D. COROLLARY . Hence every equilateral triangle ...
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Vanlige uttrykk og setninger
A B C ABCD adjacent alternate angle ABC angle ACB angle BAC angle equal base BC BC is equal bisect centre circle ABC circumference coincide common construct demonstrated describe diameter divided double draw equal angles equilateral exterior angle extremity figure fore four given point given straight line gnomon greater impossible interior join less Let ABC Let the straight likewise manner meet opposite angles opposite sides parallel parallelogram pass perpendicular PROB produced Q. E. D. PROP rectangle contained remaining remaining angle right angles segment semicircle shown sides square of AC straight line AC Take taken THEOR third touch touches the circle triangle ABC twice the rectangle vertex Wherefore whole