Elements of Geometry: Containing the First Six Books of Euclid, with a Supplement on the Quadrature of the Circle, and the Geometry of Solids ; to which are Added, Elements of Plane and Spherical TrigonometryW.E. Dean, 1836 - 311 sider |
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Resultat 1-3 av 18
Side 228
... cosine nearly equal to the radius , ) the angle itself cannot be very accurately found . If , for in- stance , the ... cosine of the arc BD , and CG the cosine of the half of BD ; whence the cosine of the half of any arc BD , of a circle ...
... cosine nearly equal to the radius , ) the angle itself cannot be very accurately found . If , for in- stance , the ... cosine of the arc BD , and CG the cosine of the half of BD ; whence the cosine of the half of any arc BD , of a circle ...
Side 229
... cosine of any arc be given , the cosine of half that arc may be found . Let BD , therefore , be equal to 60 ° , so that the chord BD = radius , then the cosine or perpendicular CF was shewn ( 9. 1. Sup . ) to be , and there- √3 fore ...
... cosine of any arc be given , the cosine of half that arc may be found . Let BD , therefore , be equal to 60 ° , so that the chord BD = radius , then the cosine or perpendicular CF was shewn ( 9. 1. Sup . ) to be , and there- √3 fore ...
Side 248
... cosine of either of the sides is to the ra- dius , as the cosine of the hypotenuse is to the cosine of the other side . The same construction remaining : In the triangle CEF , sin . CF : R : : sin . CE sin . CFE ( 19. ) ; but sin . CF ...
... cosine of either of the sides is to the ra- dius , as the cosine of the hypotenuse is to the cosine of the other side . The same construction remaining : In the triangle CEF , sin . CF : R : : sin . CE sin . CFE ( 19. ) ; but sin . CF ...
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ABC is equal ABCD adjacent angles altitude angle ABC angle ACB angle BAC angles equal arc AC base BC bisected centre chord circle ABC circumference cosine cylinder demonstrated diameter divided draw Prob equal and similar equal angles equiangular equilateral equilateral polygon equimultiples Euclid exterior angle fore four right angles given straight line greater Hence hypotenuse inscribed join less Let ABC Let the straight magnitudes meet multiple opposite angle parallel parallelogram parallelopiped perpendicular polygon prism PROP proposition quadrilateral radius ratio rectangle contained rectilineal figure remaining angle right angled triangle SCHOLIUM segment semicircle shewn side BC sine solid angle solid parallelopiped spherical angle spherical triangle square straight line BC THEOR third touches the circle triangle ABC wherefore