Elements of Geometry: Containing the First Six Books of Euclid, with a Supplement on the Quadrature of the Circle, and the Geometry of Solids: to which are Added, Edlemnts of Plane and Spherical TrigonometryW.E. Dean, 1836 - 311 sider |
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Side 206
... cylinder , for it describes that superficies ; therefore , EF is also in the superficies of the cylinder . PROP . XVII . THEOR . A cylinder and a parallelopiped having equal bases and altitudes , are equal to one another . Let ABCD be a ...
... cylinder , for it describes that superficies ; therefore , EF is also in the superficies of the cylinder . PROP . XVII . THEOR . A cylinder and a parallelopiped having equal bases and altitudes , are equal to one another . Let ABCD be a ...
Side 207
... cylinder , which will therefore be less than the cylinder , be- cause it is within it ( 16. 3. Sup . ) ; and if through the point R a plane RS parallel to NF be made to pass , it will cut off the parallelopiped ES equal ( 2. Cor . 8. 3 ...
... cylinder , which will therefore be less than the cylinder , be- cause it is within it ( 16. 3. Sup . ) ; and if through the point R a plane RS parallel to NF be made to pass , it will cut off the parallelopiped ES equal ( 2. Cor . 8. 3 ...
Side 209
... cylinders inscribed in the hemisphere , and described about the cone , is equal to a cylinder , having the same base and altitude with the hemisphere . Let the figure BCD be constructed as before , and supposed to revolve about CD ; the ...
... cylinders inscribed in the hemisphere , and described about the cone , is equal to a cylinder , having the same base and altitude with the hemisphere . Let the figure BCD be constructed as before , and supposed to revolve about CD ; the ...
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Vanlige uttrykk og setninger
ABC is equal ABCD adjacent angles altitude angle ABC angle ACB angle BAC angles equal arc AC base BC bisected centre chord circle ABC circumference cosine cylinder demonstrated diameter divided draw Prob equal and similar equal angles equiangular equilateral equilateral polygon equimultiples Euclid exterior angle fore four right angles given straight line greater Hence hypotenuse inscribed join less Let ABC Let the straight magnitudes meet multiple opposite angle parallel parallelogram parallelopiped perpendicular polygon prism PROP proposition quadrilateral radius ratio rectangle contained rectilineal figure remaining angle right angled triangle SCHOLIUM segment semicircle shewn side BC sine solid angle solid parallelopiped spherical angle spherical triangle square straight line BC THEOR third touches the circle triangle ABC wherefore