Elements of Geometry: Containing the First Six Books of Euclid, with a Supplement on the Quadrature of the Circle, and the Geometry of Solids: to which are Added, Edlemnts of Plane and Spherical TrigonometryW.E. Dean, 1836 - 311 sider |
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Resultat 1-3 av 93
Side 94
... angle BAD is equal to two right angles ; or BAD is the fifth part of two right angles . " 66 " COR . 2. Because BAD is the fifth part of two , or the tenth part of " four right angles , all the angles about the centre A are together equal ...
... angle BAD is equal to two right angles ; or BAD is the fifth part of two right angles . " 66 " COR . 2. Because BAD is the fifth part of two , or the tenth part of " four right angles , all the angles about the centre A are together equal ...
Side 119
... equal to the alternate angle CAD ( 21. 1. ) : But CAD is equal to the angle DAE ( Hyp . ) : therefore also DAE is ... angles of equiangular triangles are proportionals ; and those which are opposite to the equal angles are homologous ...
... equal to the alternate angle CAD ( 21. 1. ) : But CAD is equal to the angle DAE ( Hyp . ) : therefore also DAE is ... angles of equiangular triangles are proportionals ; and those which are opposite to the equal angles are homologous ...
Side 126
... angle of the one equal to one angle of the other , and their sides about the equal angles reciprocally proportional , are equal to one another . F E D B Let AB , BC be equal parallel- A ograms , which have the angles at B equal , and let ...
... angle of the one equal to one angle of the other , and their sides about the equal angles reciprocally proportional , are equal to one another . F E D B Let AB , BC be equal parallel- A ograms , which have the angles at B equal , and let ...
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Vanlige uttrykk og setninger
ABC is equal ABCD adjacent angles altitude angle ABC angle ACB angle BAC angles equal arc AC base BC bisected centre chord circle ABC circumference cosine cylinder demonstrated diameter divided draw Prob equal and similar equal angles equiangular equilateral equilateral polygon equimultiples Euclid exterior angle fore four right angles given straight line greater Hence hypotenuse inscribed join less Let ABC Let the straight magnitudes meet multiple opposite angle parallel parallelogram parallelopiped perpendicular polygon prism PROP proposition quadrilateral radius ratio rectangle contained rectilineal figure remaining angle right angled triangle SCHOLIUM segment semicircle shewn side BC sine solid angle solid parallelopiped spherical angle spherical triangle square straight line BC THEOR third touches the circle triangle ABC wherefore