Elements of Geometry: Containing the First Six Books of Euclid, with a Supplement on the Quadrature of the Circle, and the Geometry of Solids: to which are Added, Edlemnts of Plane and Spherical TrigonometryW.E. Dean, 1836 - 311 sider |
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Side 131
... Similar polygons may be divided into the same number of similar triangles , hav- ing the same ratio to one another that the polygons have ; and the polygons have to one another the duplicate ratio of that which their homologous sides ...
... Similar polygons may be divided into the same number of similar triangles , hav- ing the same ratio to one another that the polygons have ; and the polygons have to one another the duplicate ratio of that which their homologous sides ...
Side 133
... similar . For the similarity of the two triangles will give the angles EAB = LFG , ABE FGL , EBC = LGH : hence , ABC ... similar . PROP . XXI THEOR . Rectilineal figures which are similar to the same rectilineal figure , are also similar ...
... similar . For the similarity of the two triangles will give the angles EAB = LFG , ABE FGL , EBC = LGH : hence , ABC ... similar . PROP . XXI THEOR . Rectilineal figures which are similar to the same rectilineal figure , are also similar ...
Side 136
... similar to one another ( def . 1. 6. ) ; for the same reason , the pa- rallelogram ABCD is similar to the parallelogram FHCK . Wherefore each of the parallelograms , GE , KH is similar to DB : but rectilineal figures which are similar ...
... similar to one another ( def . 1. 6. ) ; for the same reason , the pa- rallelogram ABCD is similar to the parallelogram FHCK . Wherefore each of the parallelograms , GE , KH is similar to DB : but rectilineal figures which are similar ...
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Vanlige uttrykk og setninger
ABC is equal ABCD adjacent angles altitude angle ABC angle ACB angle BAC angles equal arc AC base BC bisected centre chord circle ABC circumference cosine cylinder demonstrated diameter divided draw Prob equal and similar equal angles equiangular equilateral equilateral polygon equimultiples Euclid exterior angle fore four right angles given straight line greater Hence hypotenuse inscribed join less Let ABC Let the straight magnitudes meet multiple opposite angle parallel parallelogram parallelopiped perpendicular polygon prism PROP proposition quadrilateral radius ratio rectangle contained rectilineal figure remaining angle right angled triangle SCHOLIUM segment semicircle shewn side BC sine solid angle solid parallelopiped spherical angle spherical triangle square straight line BC THEOR third touches the circle triangle ABC wherefore