Elements of Geometry: Containing the First Six Books of Euclid, with a Supplement on the Quadrature of the Circle, and the Geometry of Solids: to which are Added, Edlemnts of Plane and Spherical TrigonometryW.E. Dean, 1836 - 311 sider |
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Resultat 1-3 av 91
Side 13
... straight line with CB , let BE be in the same straight line with it ; therefore , because the straight line AB makes angles with the straight line CBE , upon one side of it , the angles ABC , ABE are to- gether equal ( 6. 1. ) to two ...
... straight line with CB , let BE be in the same straight line with it ; therefore , because the straight line AB makes angles with the straight line CBE , upon one side of it , the angles ABC , ABE are to- gether equal ( 6. 1. ) to two ...
Side 34
... straight line , that is , to divide it into two equal parts . Let AB be the given straight line ; it is required to divide it into two equal parts . Describe ( Prob . 1. ) upon it an equilateral triangle ABC , and bisect ( Prob . 4 ...
... straight line , that is , to divide it into two equal parts . Let AB be the given straight line ; it is required to divide it into two equal parts . Describe ( Prob . 1. ) upon it an equilateral triangle ABC , and bisect ( Prob . 4 ...
Side 38
... straight line BC in two points C ' and C , lying on the same side of B : hence , there will be two triangles BAC ' , BAC , either of which will satisfy the con- ditions of the problem . SCHOLIUM . In the last case , if the opposite side ...
... straight line BC in two points C ' and C , lying on the same side of B : hence , there will be two triangles BAC ' , BAC , either of which will satisfy the con- ditions of the problem . SCHOLIUM . In the last case , if the opposite side ...
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Vanlige uttrykk og setninger
ABC is equal ABCD adjacent angles altitude angle ABC angle ACB angle BAC angles equal arc AC base BC bisected centre chord circle ABC circumference cosine cylinder demonstrated diameter divided draw Prob equal and similar equal angles equiangular equilateral equilateral polygon equimultiples Euclid exterior angle fore four right angles given straight line greater Hence hypotenuse inscribed join less Let ABC Let the straight magnitudes meet multiple opposite angle parallel parallelogram parallelopiped perpendicular polygon prism PROP proposition quadrilateral radius ratio rectangle contained rectilineal figure remaining angle right angled triangle SCHOLIUM segment semicircle shewn side BC sine solid angle solid parallelopiped spherical angle spherical triangle square straight line BC THEOR third touches the circle triangle ABC wherefore