# University Algebra: Designed for the Use of Schools and Colleges

Leach, Shewell, and Sanborn, 1880 - 475 sider

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Side 172 - ... and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found, on the left hand of the dividend for a divisor. 4. Seek how often the divisor is contained...
Side 87 - A Complex Fraction is one having a fraction in its numerator or denominator, or both. It may be regarded as a case in division ; its numerator answering to the dividend, and its denominator to the divisor. EXAMPLES. 1. Reduce — — to it
Side 267 - Hence -,- = -76" dn that is a" : b" = c" : dn THEOREM IX. 23 1 If any number of quantities are proportional, any antecedent is to its consequent as the sum of all the antecedents is to the sum of all the consequents. Let a : b = c : d...
Side 342 - If the number is greater than 1, the characteristic is 1 less than the number of figures to the left of the decimal point.
Side 137 - A banker has two kinds of money. It takes a pieces of the first kind to make a dollar, and b pieces of the second kind. If he is offered a dollar for с pieces, how many of each kind must he give ? 81.
Side 62 - The LEAST COMMON MULTIPLE of two or more quantities is the least quantity that can be divided by each of them without a remainder.
Side 258 - A farmer bought some sheep for \$ 72, and found that if he had bought 6 more for the same money, he would have paid \$ 1 less for each. How many sheep did he buy ? OPERATION.
Side 273 - If the illumination from a source of light varies inversely as the square of the distance, how much farther from a candle must a book, which is now 15 inches off, be removed, so as to receive just one-third as much light ? 20.
Side 265 - If four quantities are in proportion, they will be in proportion by inversion; that is, the second term will be to the first as the fourth to the third.
Side 38 - The square of the difference of two quantities is equal to the square of the first, minus twice the product of the first and second, plus the square of the second. Thus, (a — 6)* = (a — b) (a — 6)=a2— 2a6 + 6'.