## Euclid's Elements of Geometry: From the Latin Translation of Commandine. To which is Added, A Treatise of the Nature of Arithmetic of Logarithms ; Likewise Another of the Elements of Plain and Spherical Trigonometry ; with a Preface |

### Inni boken

Resultat 1-5 av 5

Side 119

To which is Added, A Treatise of the Nature of Arithmetic of Logarithms ; Likewise

Another of the Elements of Plain and Spherical Trigonometry ; with a Preface

John Keill Mr. Cunn (Samuel), John Ham. be equal to 5B . Then C

to ...

To which is Added, A Treatise of the Nature of Arithmetic of Logarithms ; Likewise

Another of the Elements of Plain and Spherical Trigonometry ; with a Preface

John Keill Mr. Cunn (Samuel), John Ham. be equal to 5B . Then C

**shall be equal**to ...

Side 182

Let FL , FE , be produced , and let FLM be

complete the Parallelogram MN . Therefore MN is

GH I 1 of bis.is fimilar to EL , and so MN

...

Let FL , FE , be produced , and let FLM be

**equal**to KH , FEN**equal**to KG , andcomplete the Parallelogram MN . Therefore MN is

**equal**and similar to GÅ ; butGH I 1 of bis.is fimilar to EL , and so MN

**shall**be $ fimilar to * 26 of this . EL ; and...

Side 213

Therefore the N is greater than DEF ; but because the DE , EF , are equal to the

two Sides MX , the Base DF is equal to the Base MN , the XN

the Angle DEF ; but en proved greater , which is abfurd . ThereB is not equal to

LX .

Therefore the N is greater than DEF ; but because the DE , EF , are equal to the

two Sides MX , the Base DF is equal to the Base MN , the XN

**shall be equal**tothe Angle DEF ; but en proved greater , which is abfurd . ThereB is not equal to

LX .

Side 213

First , let it be

XL , each to each ; and the Base AC is ... Therefore AB is not

Moreover we will prove that it is not less ; wherefore it

greater .

First , let it be

**equal**; then the two Sides AB , BC , are**equal**to the two Sides MX ,XL , each to each ; and the Base AC is ... Therefore AB is not

**equal**to L X.Moreover we will prove that it is not less ; wherefore it

**shall**be necessarilygreater .

Side 230

I say the Angle GAL is

' H let HK be drawn parallel to GL ; but GL is perpendicular to the Plane passing

thro ' BAC . Therefore HK

I say the Angle GAL is

**equal**to the Angle MDN . Make A H**equal**to DM , and thro' H let HK be drawn parallel to GL ; but GL is perpendicular to the Plane passing

thro ' BAC . Therefore HK

**shall*** 8 of this . be * also perpendicular to the Plane ...### Hva folk mener - Skriv en omtale

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Euclid's Elements of Geometry: From the Latin Translation of Commandine. To ... John Keill Uten tilgangsbegrensning - 1723 |

### Vanlige uttrykk og setninger

added alſo Altitude Angle ABC Baſe becauſe Center Circle Circle ABCD Circumference common Cone conſequently contained Cylinder demonſtrated deſcribed Diameter Difference Diſtance divided double draw drawn equal equal Angles equiangular Equimultiples exceeds fall fame firſt fore four fourth given greater half join leſs likewiſe Logarithm Magnitudes Manner mean Multiple Number oppoſite parallel Parallelogram perpendicular Place Plane Point Polygon Priſms produced Prop Proportion PROPOSITION proved Pyramid Radius Ratio Rectangle remaining Right Angles Right Line Right-lined Figure ſaid ſame ſame Reaſon ſay ſecond Segment Series ſhall ſhall be equal Sides ſimilar ſince Sine Solid ſome Sphere Square ſtand taken Terms THEOREM thereof theſe third thoſe thro touch Triangle Triangle ABC Unity Wherefore whole whoſe Baſe

### Populære avsnitt

Side 66 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz.

Side 161 - IF two triangles have one angle of the one equal to one angle of the other, and the sides about the equal angles proportionals : the triangles shall be equiangular, and shall have those angles equal which are opposite to the homologous sides.

Side 110 - And in like manner it may be shown that each of the angles KHG, HGM, GML is equal to the angle HKL or KLM ; therefore the five angles GHK, HKL, KLM, LMG, MGH...

Side 88 - IN a circle, the angle in a semicircle is a right angle ; but the angle in a segment greater than a semicircle is less than a right angle ; and the angle in a segment less than a semicircle is greater than a right angle.

Side 22 - ... sides equal to them of the other. Let ABC, DEF be two triangles which have the two sides AB, AC equal to the two sides DE, DF, each to each, viz. AB...

Side 9 - ... equal to them, of the other. Let ABC, DEF be two triangles which have the two sides AB, AC equal to the two sides DE, DF, each to each, viz. AB equal to DE, and AC to DF ; but the base CB greater than the base EF ; the angle BAC is likewise greater than the angle EDF.

Side 15 - CF, and the triangle AEB to the triangle CEF, and the remaining angles to the remaining angles, each to each, to which...

Side 33 - ... therefore their other sides are equal, each to each, and the third angle of the one to the third angle of the other, (i.

Side 111 - If two right-angled triangles have their hypotenuses equal, and one side of the one equal to one side of the other, the triangles are congruent.