Euclid's Elements of Geometry,: From the Latin Translation of Commandine. To which is Added, A Treatise of the Nature of Arithmetic of Logarithms; Likewise Another of the Elements of Plain and Spherical Trigonometry; with a Preface...Tho. Woodward at the Half-Moon, between the Two Temple-Gates in Fleet-street; and sold by, 1733 - 397 sider |
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Resultat 1-5 av 52
Side 32
... join two equal and parallel Right Lines , towards the fame Parts , are also equal and parallel ; which was to be demonstrated . " Defin . A Parallelogram is a Quadrilateral Figure , each Defin . 32 Euclid's ELEMENTS . Book 1 .
... join two equal and parallel Right Lines , towards the fame Parts , are also equal and parallel ; which was to be demonstrated . " Defin . A Parallelogram is a Quadrilateral Figure , each Defin . 32 Euclid's ELEMENTS . Book 1 .
Side 33
... Parallelogram , whofe Diame- ter is BC . I fay , the oppofite Sides and opposite Angles are equal between themfelves , and the Dia- meter BC bifects the Parallelogram . * For because AB is parallel to CD , and the Right Line BC falls on ...
... Parallelogram , whofe Diame- ter is BC . I fay , the oppofite Sides and opposite Angles are equal between themfelves , and the Dia- meter BC bifects the Parallelogram . * For because AB is parallel to CD , and the Right Line BC falls on ...
Side 34
... Parallelogram ACDB ; which was to be demonftrated . PROPOSITION XXXV . THEOREM . Parallelograms conftituted upon the ... Parallelogram EBCF . For because ABCD is a Parallelogram , AD is 34 of this equal to BC ; and for the fame Reason EF ...
... Parallelogram ACDB ; which was to be demonftrated . PROPOSITION XXXV . THEOREM . Parallelograms conftituted upon the ... Parallelogram EBCF . For because ABCD is a Parallelogram , AD is 34 of this equal to BC ; and for the fame Reason EF ...
Side 35
... Parallelogram ABCD is equal to the Parallelogram EFGH . * 35 of this . For join BE , CH . Then becaufe BC is equal * Hyp . to F G , and FG to EH ; BC will be likewife equal to EH ; and they are parallel , and BE , CH , joins them . But ...
... Parallelogram ABCD is equal to the Parallelogram EFGH . * 35 of this . For join BE , CH . Then becaufe BC is equal * Hyp . to F G , and FG to EH ; BC will be likewife equal to EH ; and they are parallel , and BE , CH , joins them . But ...
Side 36
... Parallelogram EBCA is equal to the Parallelogram DBCF ; for they ftand upon the fame Base BC , and between the fame Parallels B C , † 34 of this . EF . But the Triangle ABC is † one half of the Pa- rallelogram E BCA , because the ...
... Parallelogram EBCA is equal to the Parallelogram DBCF ; for they ftand upon the fame Base BC , and between the fame Parallels B C , † 34 of this . EF . But the Triangle ABC is † one half of the Pa- rallelogram E BCA , because the ...
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Euclid's Elements of Geometry: From the Latin Translation of Commandine. to ... John Keill Ingen forhåndsvisning tilgjengelig - 2014 |
Vanlige uttrykk og setninger
adjacent Angles alfo equal alſo Angle ABC Angle BAC Bafe Baſe becauſe bifected Center Circle ABCD Circumference Cofine Cone confequently Coroll Cylinder defcribed demonftrated Diameter Diſtance drawn thro EFGH equal Angles equiangular Equimultiples faid fame Altitude fame Multiple fame Plane fame Proportion fame Reaſon fecond fhall be equal fimilar fince firft firſt folid Parallelepipedon fome fore ftand fubtending given Right Line Gnomon greater join leffer lefs leſs likewife Logarithm Magnitudes Meaſure Number Parallelogram perpendicular Polygon Priſms Prop PROPOSITION Pyramid Pyramid ABCG Quadrant Ratio Rectangle Rectangle contained remaining Angle Right Angles Right Line AC Right-lined Figure Segment ſhall Sine Solid Sphere Subtangent themſelves THEOREM theſe thofe thoſe Triangle ABC Unity Vertex the Point Wherefore whofe Bafe whole whoſe Baſe
Populære avsnitt
Side 66 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz.
Side 163 - IF two triangles have one angle of the one equal to one angle of the other, and the sides about the equal angles proportionals : the triangles shall be equiangular, and shall have those angles equal which are opposite to the homologous sides.
Side 112 - And in like manner it may be shown that each of the angles KHG, HGM, GML is equal to the angle HKL or KLM ; therefore the five angles GHK, HKL, KLM, LMG, MGH...
Side 90 - IN a circle, the angle in a semicircle is a right angle ; but the angle in a segment greater than a semicircle is less than a right angle ; and the angle in a segment less than a semicircle is greater than a right angle.
Side 22 - ... sides equal to them of the other. Let ABC, DEF be two triangles which have the two sides AB, AC equal to the two sides DE, DF, each to each, viz. AB...
Side 10 - ... equal to them, of the other. Let ABC, DEF be two triangles which have the two sides AB, AC equal to the two sides DE, DF, each to each, viz. AB equal to DE, and AC to DF ; but the base CB greater than the base EF ; the angle BAC is likewise greater than the angle EDF.
Side 15 - CF, and the triangle AEB to the triangle CEF, and the remaining angles to the remaining angles, each to each, to which...
Side 33 - ... therefore their other sides are equal, each to each, and the third angle of the one to the third angle of the other, (i.
Side 113 - If two right-angled triangles have their hypotenuses equal, and one side of the one equal to one side of the other, the triangles are congruent.