## Euclid's Elements of Geometry: From the Latin Translation of Commandine. To which is Added, A Treatise of the Nature of Arithmetic of Logarithms ; Likewise Another of the Elements of Plain and Spherical Trigonometry ; with a Preface |

### Inni boken

Resultat 1-5 av 5

Side 64

Tī

, when some Point is taken in the Circumference thereof , and from it Right Lines

are

Tī

**drawn**in it , which * bisect in the Point VIII . An Angle is said to be in a Segment, when some Point is taken in the Circumference thereof , and from it Right Lines

are

**drawn**to the Ends of that Right Line , which is the Base of the Segment ... Side 66

THEOREM . if in a Circle a Right Line

Right Line not

Angles ; and if it cuts it at Right Angles , it all cut it into two equal Parts . ET ABC

be a ...

THEOREM . if in a Circle a Right Line

**drawn**thro ' the Center , cuts any otherRight Line not

**drawn**throm the Center , into equal Parts , it fall cut it at RightAngles ; and if it cuts it at Right Angles , it all cut it into two equal Parts . ET ABC

be a ...

Side 67

If in a Circle two Right Lines not being

they will not cut each other into two equal Parts . L ET ABCD be a Circle , wherein

two Right Lines AC , BD , not

...

If in a Circle two Right Lines not being

**drawn**tbro ' the Center , cut each other ,they will not cut each other into two equal Parts . L ET ABCD be a Circle , wherein

two Right Lines AC , BD , not

**drawn**thro ' the Center , cut each other in the Point...

Side 79

PROPOSITION XVI . THEOREM . A Line

Dia . meter of a Circle at Right Angles to that Diameter , Mall fall without the Circle

; and between the said Right Line , and the Circumference , no other Line can be

...

PROPOSITION XVI . THEOREM . A Line

**drawn**from the extreme [ Point ] of theDia . meter of a Circle at Right Angles to that Diameter , Mall fall without the Circle

; and between the said Right Line , and the Circumference , no other Line can be

...

Side 200

PROBLEM , From a Point given ałote a Plarie , to

perpendicular to that Plane . L 12. 1 . ... Let a Right Line B C be any how

the Plane BH , and let AD be

if AD be ...

PROBLEM , From a Point given ałote a Plarie , to

**draw**a Right Lineperpendicular to that Plane . L 12. 1 . ... Let a Right Line B C be any how

**drawn**inthe Plane BH , and let AD be

**drawn*** from the Point A perpendicular to BC ; thenif AD be ...

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Euclid's Elements of Geometry: From the Latin Translation of Commandine. To ... John Keill Uten tilgangsbegrensning - 1723 |

### Vanlige uttrykk og setninger

added alſo Altitude Angle ABC Baſe becauſe Center Circle Circle ABCD Circumference common Cone conſequently contained Cylinder demonſtrated deſcribed Diameter Difference Diſtance divided double draw drawn equal equal Angles equiangular Equimultiples exceeds fall fame firſt fore four fourth given greater half join leſs likewiſe Logarithm Magnitudes Manner mean Multiple Number oppoſite parallel Parallelogram perpendicular Place Plane Point Polygon Priſms produced Prop Proportion PROPOSITION proved Pyramid Radius Ratio Rectangle remaining Right Angles Right Line Right-lined Figure ſaid ſame ſame Reaſon ſay ſecond Segment Series ſhall ſhall be equal Sides ſimilar ſince Sine Solid ſome Sphere Square ſtand taken Terms THEOREM thereof theſe third thoſe thro touch Triangle Triangle ABC Unity Wherefore whole whoſe Baſe

### Populære avsnitt

Side 66 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz.

Side 161 - IF two triangles have one angle of the one equal to one angle of the other, and the sides about the equal angles proportionals : the triangles shall be equiangular, and shall have those angles equal which are opposite to the homologous sides.

Side 110 - And in like manner it may be shown that each of the angles KHG, HGM, GML is equal to the angle HKL or KLM ; therefore the five angles GHK, HKL, KLM, LMG, MGH...

Side 88 - IN a circle, the angle in a semicircle is a right angle ; but the angle in a segment greater than a semicircle is less than a right angle ; and the angle in a segment less than a semicircle is greater than a right angle.

Side 22 - ... sides equal to them of the other. Let ABC, DEF be two triangles which have the two sides AB, AC equal to the two sides DE, DF, each to each, viz. AB...

Side 9 - ... equal to them, of the other. Let ABC, DEF be two triangles which have the two sides AB, AC equal to the two sides DE, DF, each to each, viz. AB equal to DE, and AC to DF ; but the base CB greater than the base EF ; the angle BAC is likewise greater than the angle EDF.

Side 15 - CF, and the triangle AEB to the triangle CEF, and the remaining angles to the remaining angles, each to each, to which...

Side 33 - ... therefore their other sides are equal, each to each, and the third angle of the one to the third angle of the other, (i.

Side 111 - If two right-angled triangles have their hypotenuses equal, and one side of the one equal to one side of the other, the triangles are congruent.