Euclid's Elements of Geometry,: From the Latin Translation of Commandine. To which is Added, A Treatise of the Nature of Arithmetic of Logarithms; Likewise Another of the Elements of Plain and Spherical Trigonometry; with a Preface...Tho. Woodward at the Half-Moon, between the Two Temple-Gates in Fleet-street; and sold by, 1733 - 397 sider |
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Resultat 1-5 av 82
Side 10
... drawn from a certain Point within the Figure , are equal . XVI . And that Point is called the Center of the Circle . XVII . A Diameter of a Circle , is a Right Line drawn through the Center , and terminated on both Sides by the ...
... drawn from a certain Point within the Figure , are equal . XVI . And that Point is called the Center of the Circle . XVII . A Diameter of a Circle , is a Right Line drawn through the Center , and terminated on both Sides by the ...
Side 29
... thro ' a given Point parallel to a given Right Line . LE ET A be a Point given , and BC a Right Line given . It is ... drawn thro ' the given Point A , parallel to the given Right Line BC ; which was to be done . Coroll . * 31 of this ...
... thro ' a given Point parallel to a given Right Line . LE ET A be a Point given , and BC a Right Line given . It is ... drawn thro ' the given Point A , parallel to the given Right Line BC ; which was to be done . Coroll . * 31 of this ...
Side 30
... drawn thro ' the Point C parallel to the Right Line AB . Then because AB is parallel to CE , and AC falls upon them , the alternate Angles t29 of this . BAC , ACE , are † equal between themselves . Again , because AB is parallel to CE ...
... drawn thro ' the Point C parallel to the Right Line AB . Then because AB is parallel to CE , and AC falls upon them , the alternate Angles t29 of this . BAC , ACE , are † equal between themselves . Again , because AB is parallel to CE ...
Side 35
... through B draw * BÉ parallel to CA ; and * 31 of thit . through C , CF , parallel to BD . D Where- Wherefore both EBCA , DBCF , are Parallelo- * 35 Book I. Euclid's ELEMENTS . 35.
... through B draw * BÉ parallel to CA ; and * 31 of thit . through C , CF , parallel to BD . D Where- Wherefore both EBCA , DBCF , are Parallelo- * 35 Book I. Euclid's ELEMENTS . 35.
Side 36
... thro ' B draw BG parallel to CA ; and thro ' E , EH , parallel to DC . Wherefore both GBCA , DCEH , are Paralle- lograms , and the Parallelogram GBCA is † equal † 36 of this to the Parallelogram DCEH : For they ftand upon equal Bafes ...
... thro ' B draw BG parallel to CA ; and thro ' E , EH , parallel to DC . Wherefore both GBCA , DCEH , are Paralle- lograms , and the Parallelogram GBCA is † equal † 36 of this to the Parallelogram DCEH : For they ftand upon equal Bafes ...
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Euclid's Elements of Geometry: From the Latin Translation of Commandine. to ... John Keill Ingen forhåndsvisning tilgjengelig - 2014 |
Vanlige uttrykk og setninger
adjacent Angles alfo equal alſo Angle ABC Angle BAC Bafe Baſe becauſe bifected Center Circle ABCD Circumference Cofine Cone confequently Coroll Cylinder defcribed demonftrated Diameter Diſtance drawn thro EFGH equal Angles equiangular Equimultiples faid fame Altitude fame Multiple fame Plane fame Proportion fame Reaſon fecond fhall be equal fimilar fince firft firſt folid Parallelepipedon fome fore ftand fubtending given Right Line Gnomon greater join leffer lefs leſs likewife Logarithm Magnitudes Meaſure Number Parallelogram perpendicular Polygon Priſms Prop PROPOSITION Pyramid Pyramid ABCG Quadrant Ratio Rectangle Rectangle contained remaining Angle Right Angles Right Line AC Right-lined Figure Segment ſhall Sine Solid Sphere Subtangent themſelves THEOREM theſe thofe thoſe Triangle ABC Unity Vertex the Point Wherefore whofe Bafe whole whoſe Baſe
Populære avsnitt
Side 66 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz.
Side 163 - IF two triangles have one angle of the one equal to one angle of the other, and the sides about the equal angles proportionals : the triangles shall be equiangular, and shall have those angles equal which are opposite to the homologous sides.
Side 112 - And in like manner it may be shown that each of the angles KHG, HGM, GML is equal to the angle HKL or KLM ; therefore the five angles GHK, HKL, KLM, LMG, MGH...
Side 90 - IN a circle, the angle in a semicircle is a right angle ; but the angle in a segment greater than a semicircle is less than a right angle ; and the angle in a segment less than a semicircle is greater than a right angle.
Side 22 - ... sides equal to them of the other. Let ABC, DEF be two triangles which have the two sides AB, AC equal to the two sides DE, DF, each to each, viz. AB...
Side 10 - ... equal to them, of the other. Let ABC, DEF be two triangles which have the two sides AB, AC equal to the two sides DE, DF, each to each, viz. AB equal to DE, and AC to DF ; but the base CB greater than the base EF ; the angle BAC is likewise greater than the angle EDF.
Side 15 - CF, and the triangle AEB to the triangle CEF, and the remaining angles to the remaining angles, each to each, to which...
Side 33 - ... therefore their other sides are equal, each to each, and the third angle of the one to the third angle of the other, (i.
Side 113 - If two right-angled triangles have their hypotenuses equal, and one side of the one equal to one side of the other, the triangles are congruent.