Euclid's Elements of Geometry: From the Latin Translation of Commandine. To which is Added, A Treatise of the Nature of Arithmetic of Logarithms ; Likewise Another of the Elements of Plain and Spherical Trigonometry ; with a Preface |
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Resultat 1-5 av 6
Side 37
ÉT ABC , DB C , bè equal Triangles , constituted upon the fame Base B C , on the
fame Side . I say they are between the fame Parallels . For let AD be drawn . I say
A D is parallel to B C. For if it be not parallel , draw * the Right Line AE * 31 of ...
ÉT ABC , DB C , bè equal Triangles , constituted upon the fame Base B C , on the
fame Side . I say they are between the fame Parallels . For let AD be drawn . I say
A D is parallel to B C. For if it be not parallel , draw * the Right Line AE * 31 of ...
Side 138
P K Because GH is the same Multiple of AE as HK is of B N * I of this E B .;
therefore GH * is the fame Multiple of A E , as GK D E M is of AB . But GH is the F
fame Multiple of AE , as LM is of CF. Wherefore GK G C L is the fame Multiple of
AB , 25 ...
P K Because GH is the same Multiple of AE as HK is of B N * I of this E B .;
therefore GH * is the fame Multiple of A E , as GK D E M is of AB . But GH is the F
fame Multiple of AE , as LM is of CF. Wherefore GK G C L is the fame Multiple of
AB , 25 ...
Side 219
Solid Parallelepipedons , being constituted upon the Jame Base , and having the
fame Altitude , and whose insistent Lines are in the fame Right Lines , are equal
to one another . ET the folid Parallelepipedons CM , CN , be upon the fame ...
Solid Parallelepipedons , being constituted upon the Jame Base , and having the
fame Altitude , and whose insistent Lines are in the fame Right Lines , are equal
to one another . ET the folid Parallelepipedons CM , CN , be upon the fame ...
Side 222
Again , becaufe the Parallelogram RY XT is equal to the Parallelogram _T , for it
stands on the fame Base RT , and between the same Parallels RT , 12 X ; and the
Parallelogram RYXT is equal to the Parallelogram CD , because it is alfo equal ...
Again , becaufe the Parallelogram RY XT is equal to the Parallelogram _T , for it
stands on the fame Base RT , and between the same Parallels RT , 12 X ; and the
Parallelogram RYXT is equal to the Parallelogram CD , because it is alfo equal ...
Side 270
And for the fame Reason , each of the quadrilateral Figures SOPT , TPRY , are in
one Plane , And the Triangle YRX , is † in one Plane . There's fore , if Right Lines
be supposed to be drawn from the Points O , S , P , T , R , Y , to the Point A ...
And for the fame Reason , each of the quadrilateral Figures SOPT , TPRY , are in
one Plane , And the Triangle YRX , is † in one Plane . There's fore , if Right Lines
be supposed to be drawn from the Points O , S , P , T , R , Y , to the Point A ...
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Euclid's Elements of Geometry: From the Latin Translation of Commandine. To ... John Keill Uten tilgangsbegrensning - 1723 |
Vanlige uttrykk og setninger
added alſo Altitude Angle ABC Baſe becauſe Center Circle Circle ABCD Circumference common Cone conſequently contained Cylinder demonſtrated deſcribed Diameter Difference Diſtance divided double draw drawn equal equal Angles equiangular Equimultiples exceeds fall fame firſt fore four fourth given greater half join leſs likewiſe Logarithm Magnitudes Manner mean Multiple Number oppoſite parallel Parallelogram perpendicular Place Plane Point Polygon Priſms produced Prop Proportion PROPOSITION proved Pyramid Radius Ratio Rectangle remaining Right Angles Right Line Right-lined Figure ſaid ſame ſame Reaſon ſay ſecond Segment Series ſhall ſhall be equal Sides ſimilar ſince Sine Solid ſome Sphere Square ſtand taken Terms THEOREM thereof theſe third thoſe thro touch Triangle Triangle ABC Unity Wherefore whole whoſe Baſe
Populære avsnitt
Side 66 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz.
Side 161 - IF two triangles have one angle of the one equal to one angle of the other, and the sides about the equal angles proportionals : the triangles shall be equiangular, and shall have those angles equal which are opposite to the homologous sides.
Side 110 - And in like manner it may be shown that each of the angles KHG, HGM, GML is equal to the angle HKL or KLM ; therefore the five angles GHK, HKL, KLM, LMG, MGH...
Side 88 - IN a circle, the angle in a semicircle is a right angle ; but the angle in a segment greater than a semicircle is less than a right angle ; and the angle in a segment less than a semicircle is greater than a right angle.
Side 22 - ... sides equal to them of the other. Let ABC, DEF be two triangles which have the two sides AB, AC equal to the two sides DE, DF, each to each, viz. AB...
Side 9 - ... equal to them, of the other. Let ABC, DEF be two triangles which have the two sides AB, AC equal to the two sides DE, DF, each to each, viz. AB equal to DE, and AC to DF ; but the base CB greater than the base EF ; the angle BAC is likewise greater than the angle EDF.
Side 15 - CF, and the triangle AEB to the triangle CEF, and the remaining angles to the remaining angles, each to each, to which...
Side 33 - ... therefore their other sides are equal, each to each, and the third angle of the one to the third angle of the other, (i.
Side 111 - If two right-angled triangles have their hypotenuses equal, and one side of the one equal to one side of the other, the triangles are congruent.