Euclid's Elements of Geometry: From the Latin Translation of Commandine. To which is Added, A Treatise of the Nature of Arithmetic of Logarithms ; Likewise Another of the Elements of Plain and Spherical Trigonometry ; with a Preface |
Inni boken
Resultat 1-5 av 8
Side 11
To draw a Right Line at Right Angles to a given Right Line , from a given Point in
the same . ET A B be the given Right Line , and the given Point . It is required to
draw a Right Line from the Point C , at Right Angles to A B. Afsume any Point D in
...
To draw a Right Line at Right Angles to a given Right Line , from a given Point in
the same . ET A B be the given Right Line , and the given Point . It is required to
draw a Right Line from the Point C , at Right Angles to A B. Afsume any Point D in
...
Side 22
With a given Right Line , and at a given Point in it , to make a Right - lin'd Angle
equal to a Right - lin'd Angle given . ET the given Right Line be A B , and the
Point given therein A , and the given Right - lined Angle DCĒ . It is required to
make a ...
With a given Right Line , and at a given Point in it , to make a Right - lin'd Angle
equal to a Right - lin'd Angle given . ET the given Right Line be A B , and the
Point given therein A , and the given Right - lined Angle DCĒ . It is required to
make a ...
Side 40
To apply a Parallelogram to a given Right Line , equal to a given Triangle , in a
given Right - lined Angle . LA ET the Right Line given be AB , the given Triangle
C , and the given Right - lined Angle D. It is required to the given Right Line AB ,
to ...
To apply a Parallelogram to a given Right Line , equal to a given Triangle , in a
given Right - lined Angle . LA ET the Right Line given be AB , the given Triangle
C , and the given Right - lined Angle D. It is required to the given Right Line AB ,
to ...
Side 202
THEOR E M. Two Right Lines cannct be erected at Right Angles , to a given
Plane from a Point ( herein given . FAR OR , if it is poffible , let two Right Lincs AB
, AC , be erected perpendicular to a given Plane on the same Side , at a given
Point ...
THEOR E M. Two Right Lines cannct be erected at Right Angles , to a given
Plane from a Point ( herein given . FAR OR , if it is poffible , let two Right Lincs AB
, AC , be erected perpendicular to a given Plane on the same Side , at a given
Point ...
Side 278
The Sine DE of any Arc DB being given , to find DM or B M tbe Sine of half the Arc
. DE being given , CE ( by the last Prop . ) will be given , and accordingly E B
which is the Difference between the Cofine and Radius . Therefore DE , EB ,
being ...
The Sine DE of any Arc DB being given , to find DM or B M tbe Sine of half the Arc
. DE being given , CE ( by the last Prop . ) will be given , and accordingly E B
which is the Difference between the Cofine and Radius . Therefore DE , EB ,
being ...
Hva folk mener - Skriv en omtale
Vi har ikke funnet noen omtaler på noen av de vanlige stedene.
Andre utgaver - Vis alle
Euclid's Elements of Geometry: From the Latin Translation of Commandine. To ... John Keill Uten tilgangsbegrensning - 1723 |
Vanlige uttrykk og setninger
added alſo Altitude Angle ABC Baſe becauſe Center Circle Circle ABCD Circumference common Cone conſequently contained Cylinder demonſtrated deſcribed Diameter Difference Diſtance divided double draw drawn equal equal Angles equiangular Equimultiples exceeds fall fame firſt fore four fourth given greater half join leſs likewiſe Logarithm Magnitudes Manner mean Multiple Number oppoſite parallel Parallelogram perpendicular Place Plane Point Polygon Priſms produced Prop Proportion PROPOSITION proved Pyramid Radius Ratio Rectangle remaining Right Angles Right Line Right-lined Figure ſaid ſame ſame Reaſon ſay ſecond Segment Series ſhall ſhall be equal Sides ſimilar ſince Sine Solid ſome Sphere Square ſtand taken Terms THEOREM thereof theſe third thoſe thro touch Triangle Triangle ABC Unity Wherefore whole whoſe Baſe
Populære avsnitt
Side 66 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz.
Side 161 - IF two triangles have one angle of the one equal to one angle of the other, and the sides about the equal angles proportionals : the triangles shall be equiangular, and shall have those angles equal which are opposite to the homologous sides.
Side 110 - And in like manner it may be shown that each of the angles KHG, HGM, GML is equal to the angle HKL or KLM ; therefore the five angles GHK, HKL, KLM, LMG, MGH...
Side 88 - IN a circle, the angle in a semicircle is a right angle ; but the angle in a segment greater than a semicircle is less than a right angle ; and the angle in a segment less than a semicircle is greater than a right angle.
Side 22 - ... sides equal to them of the other. Let ABC, DEF be two triangles which have the two sides AB, AC equal to the two sides DE, DF, each to each, viz. AB...
Side 9 - ... equal to them, of the other. Let ABC, DEF be two triangles which have the two sides AB, AC equal to the two sides DE, DF, each to each, viz. AB equal to DE, and AC to DF ; but the base CB greater than the base EF ; the angle BAC is likewise greater than the angle EDF.
Side 15 - CF, and the triangle AEB to the triangle CEF, and the remaining angles to the remaining angles, each to each, to which...
Side 33 - ... therefore their other sides are equal, each to each, and the third angle of the one to the third angle of the other, (i.
Side 111 - If two right-angled triangles have their hypotenuses equal, and one side of the one equal to one side of the other, the triangles are congruent.