Euclid's Elements of Geometry,: From the Latin Translation of Commandine. To which is Added, A Treatise of the Nature of Arithmetic of Logarithms; Likewise Another of the Elements of Plain and Spherical Trigonometry; with a Preface...Tho. Woodward at the Half-Moon, between the Two Temple-Gates in Fleet-street; and sold by, 1733 - 397 sider |
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Resultat 1-5 av 98
Side 10
... join FC , GB . Then because A F is equal to A G , and A B to AC , the two Right Lines F A , AC , are equal to the two Lines GA , AB , each to each , and contain the com- + 4 of this . mon Angle FAG ; therefore the Base F C is equal t to ...
... join FC , GB . Then because A F is equal to A G , and A B to AC , the two Right Lines F A , AC , are equal to the two Lines GA , AB , each to each , and contain the com- + 4 of this . mon Angle FAG ; therefore the Base F C is equal t to ...
Side 10
... join DC . Then because D B is equal to † 3 of this . A C , and BC is common , DB , BC , will be equal to AC , CB , each to each , and the Angle DBC equal to the Angle ACB , from the Hypothefis ; therefore the Base DC is equal to the ...
... join DC . Then because D B is equal to † 3 of this . A C , and BC is common , DB , BC , will be equal to AC , CB , each to each , and the Angle DBC equal to the Angle ACB , from the Hypothefis ; therefore the Base DC is equal to the ...
Side 10
... join + 1 of this . DE , and thereon make † the Equilateral Triangle DEF , and join A F. I fay , the Angle B A C is cut into two equal Parts by the Line A F. For because AD is equal to A E , and AF is com- mon , the two Sides DA , A F ...
... join + 1 of this . DE , and thereon make † the Equilateral Triangle DEF , and join A F. I fay , the Angle B A C is cut into two equal Parts by the Line A F. For because AD is equal to A E , and AF is com- mon , the two Sides DA , A F ...
Side 11
... join FC . I fay , the Right Line FC is drawn from the Point C , given in the Right Line A B at Right Angles to AB . * t 3 of this of this . For because DC is equal to CE , and F C is com- mon , the two Lines DC , CF , are each equal to ...
... join FC . I fay , the Right Line FC is drawn from the Point C , given in the Right Line A B at Right Angles to AB . * t 3 of this of this . For because DC is equal to CE , and F C is com- mon , the two Lines DC , CF , are each equal to ...
Side 15
... join BE , which pro- * 10 of this duce to F , and make EF equal to BE . Moreover , join FC , and produce A C to G. Then , because AE is equal to EC , and BE to EF , the two Sides AE , EB , are equal to the two Sides CE , EF , each to ...
... join BE , which pro- * 10 of this duce to F , and make EF equal to BE . Moreover , join FC , and produce A C to G. Then , because AE is equal to EC , and BE to EF , the two Sides AE , EB , are equal to the two Sides CE , EF , each to ...
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Euclid's Elements of Geometry: From the Latin Translation of Commandine. to ... John Keill Ingen forhåndsvisning tilgjengelig - 2014 |
Vanlige uttrykk og setninger
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Populære avsnitt
Side 66 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz.
Side 163 - IF two triangles have one angle of the one equal to one angle of the other, and the sides about the equal angles proportionals : the triangles shall be equiangular, and shall have those angles equal which are opposite to the homologous sides.
Side 112 - And in like manner it may be shown that each of the angles KHG, HGM, GML is equal to the angle HKL or KLM ; therefore the five angles GHK, HKL, KLM, LMG, MGH...
Side 90 - IN a circle, the angle in a semicircle is a right angle ; but the angle in a segment greater than a semicircle is less than a right angle ; and the angle in a segment less than a semicircle is greater than a right angle.
Side 22 - ... sides equal to them of the other. Let ABC, DEF be two triangles which have the two sides AB, AC equal to the two sides DE, DF, each to each, viz. AB...
Side 10 - ... equal to them, of the other. Let ABC, DEF be two triangles which have the two sides AB, AC equal to the two sides DE, DF, each to each, viz. AB equal to DE, and AC to DF ; but the base CB greater than the base EF ; the angle BAC is likewise greater than the angle EDF.
Side 15 - CF, and the triangle AEB to the triangle CEF, and the remaining angles to the remaining angles, each to each, to which...
Side 33 - ... therefore their other sides are equal, each to each, and the third angle of the one to the third angle of the other, (i.
Side 113 - If two right-angled triangles have their hypotenuses equal, and one side of the one equal to one side of the other, the triangles are congruent.