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And in like manner it may be shown that each of the angles KHG, HGM, GML is equal to the angle HKL or KLM ; therefore the five angles GHK, HKL, KLM, LMG, MGH...
Euclid's Elements of Geometry: From the Latin Translation of Commandine. To ... - Side 110
av John Keill - 1733 - 397 sider
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## Euclid's Elements of Geometry: From the Latin Translation of Commandine. To ...

John Keill - 1723 - 364 sider
...every of the Angles KHG,HGM,GML, is equal to the Angle HKL, or KLM. Therefore the fiveAngles GHK,HKL, KLM, LMG, MGH, are equal between themfelves. And fo...equilateral, and defcribed about the Circle ABCDE j •which was to be dune. PROPOSITION XIII, PROBLEM. To tinfcribe a Circle in an equilateral and equiangular...
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## The Elements of Euclid: The Errors, by which Theon, Or Others, Have Long Ago ...

Robert Simson - 1762 - 466 sider
...before demonftrated ; the angle HKL is equal to KLM. and in like manner it may be fliewn, that each of the angles KHG, HGM, GML is equal to the angle...therefore the five angles GHK, HKL, KLM, LMG, MGH being equal to one another, the pentagon GHKLM is equiangular. and it is equilateral, as was demonftrated...
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## Euclid's Elements of Geometry: The First Six, the Eleventh and Twelfth Books

Euclid, Edmund Stone - 1765 - 464 sider
...We demonftrate after the fame manner that the angles KHG, HGM, GML are each equal to the angles HKL, KLM: Therefore the five angles GHK, HKL, KLM, LMG, MGH are equal to one another. Wherefore the I pentagon GHK t M is equiangular. But it has alfo been proved to be...
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## The Elements of Euclid, Viz: The Errors, by which Theon, Or Others, Have ...

Robert Simson - 1775 - 520 sider
...the angle HKL is equal to KLM : And in like manner it may be fhewn, that each of the angles KHG, HGMi GML is equal to the angle HKL or KLM : Therefore the five angles GHK, HKL, KLM, LMG, MGH being equal to one another, the pentagon GHKLM is equiangular : And it is et;uil.ttcr.tl, as was demonftrated...
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## The Elements of Euclid: With Dissertations Intended to Assist and Encourage ...

Euclid, James Williamson - 1781 - 309 sider
...manner each of the angles KHG, HGM, GML will be demonftrated to be equal to either of the angles HKL, KLM; therefore the five angles GHK, HKL, KLM, LMG, MGH are equal to one another : therefore the pentagon GHKLM is equiangular ; but it has been alfo demonftrated to...
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## Elements of Geometry: Containing the First Six Books of Euclid, with Two ...

John Playfair - 1795 - 400 sider
...before demonftrated, the angle HKL is equal to KLM : and in like manner it may be fliown, that each of the angles KHG, HGM, GML is equal to the angle...therefore the five angles GHK, HKL, KLM, LMG, MGH being equal to one another, the pentagon GHKLM is equiangular : and it is equilateral, as was demouftrated...
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## The Elements of Euclid: Also the Book of Euclid's Data ...cor. viz. The ...

Robert Simson - 1804
...was before demonftrated; the angle HKL is equal to KLM. and in like manner it may be fhewn, that each of the angles KHG, HGM, GML is equal to the angle...therefore the five angles GHK, HKL, KLM, LMG, MGH being equal to one another, the pentagon GHKLM is equiangular, and it is equilateral, as was demonftrated;...
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## The Elements of Euclid: The Errors, by which Theon, Or Others, Have Long Ago ...

Robert Simson - 1806 - 518 sider
...angle HKL is equal to KLM: and in like manner it may be shown, that each of the angles KHG, ! IG.M, GML is equal to the angle HKL or KLM : therefore the five angles GHK, HKL, KLM, LMG, MGH being equal to one another, the pentagon GHKLM is equiangular : and it is equilateral, as -was demonstrated...
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## Elements of Geometry: Containing the First Six Books of Euclid, with a ...

John Playfair - 1806 - 311 sider
...as was before demonstrated, the angle HKL is equal to KLM. In like manner it may be shown that each of the angles KHG, HGM, GML is equal to the angle HKL, of KLM. Therefore the Book IV. five angles GHK, HKL, KLM, LMG, MGH being equal to one another, the...
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## The Elements of Euclid: Viz. the First Six Books, Together with the Eleventh ...

Euclides - 1816 - 528 sider
...before demonstrated, the angle HKL is equal to KLM : And in like manner it may be shown, that each of the angles KHG, HGM, GML is equal to the angle...Therefore the five angles GHK, HKL, KLM, LMG, MGH, being tqual to one another, the pentagon GHKLM is equiangular: And it is equilateral, as was demonstrated;...
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